Answer:
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Explanation:
Mole fraction for silver= 0.2317643/0.3079193
= 0.7526787
Mole fraction for gold=0.076155/0.3079193
=0.2473212
What is Molar Fraction?
The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight. It serves as a means of indicating how concentrated a solution is.
It is a unit of concentration, defined as the product of the moles of a component and the moles of the entire solution. When all the parts of a solution are summed up, their mole fraction equals 1.
molar mass of silver = 107.8682g/mol
Molar mass of gold= 196.96657g/mol
Therefore mole = mass/molar mass
For silver: 25g/107.8682g/mol = 0.2317643mol
For gold: 15g/196.96657g/mol= 0.076155mol
Total number of mole= 0.2317643+0.076155
= 0.30791193mol
Mole fraction for silver= 0.2317643/0.3079193
= 0.7526787
Mole fraction for gold=0.076155/0.3079193
=0.2473212
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Answer:
E 1: cyclohexene
Explanation:
This reaction is an example of the dehydration of cyclic alcohols. The reaction proceeds in the following steps;
1) The first step of the process is the protonation of the cyclohexanol by the acid. This now yields H2O^+ attached to the cyclohexane ring.
2) the water molecule, which a good leaving group now leaves yielding a carbocation. This now leaves a cyclohexane carbocation which is highly reactive.
3) A water molecule now abstracts a proton from the carbon adjacent to the carbocation leading to the formation of cyclohexene and the regeneration of the acid catalyst. This is an E1 mechanism because it proceeds via a carbocation intermediate and not a concerted transition state, hence the answer.
If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).
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What is base dissociation constant?
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The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.
The dissociation reaction of hydrogen cyanide can be given as
HCN --- (H+) + (CN-)
Given,
The value of Ka for HCN is 2.8× 10^(-9)
The correlation between base dissociation constant and acid dissociation constant is
Kw = Ka × Kb
Kw = 10^(-14)
Substituting values of Ka and Kw,
Kb = 10^(-14) /{2.8×10^(-9) }
= 3.5× 10^(-6)
Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).
DISCLAIMER: The above question have mistake. The correct question is given as
Question:
Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?
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