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alina1380 [7]
3 years ago
8

The core of the pyruvate dehydrogenase complex is made up of eight catalytic________that make up the_______component.

Chemistry
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

(D.)

The core of the pyruvate dehydrogenase complex is made up of eight catalytic <u>trimers </u>that make up the<u> E2</u> component.

Explanation:

Eight trimers assemble as a hollow truncated cube, which forms the core of the multi-enzyme complex, known as the E2 complex in human pyruvate dehydrogenase complex.

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Answer:

vb

Explanation:

b

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3 years ago
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A alkaline earth metal is an element is groups 3-12 of the periodic table true or false?
Karo-lina-s [1.5K]

False Alkaline earth metals is group 2

5 0
2 years ago
What is the molarity of a solution in which 55. 49 g of calcium chloride is dissolved in enough water to make 500. ml of solutio
PSYCHO15rus [73]

The molarity of a solution in which 55. 49 g of calcium chloride is dissolved in enough water to make 500. ml of solution is 1M.

<h3>What is molarity? </h3>

It is defined as number of moles of solute divided by volume of solution.

Given,

Mass of CaCl2 =55.49g

Molar mass of CaCl2 =40+35+35=110g

Mole= given mass/ molar mass

= 55.49/110=0.50mol.

Now, putting all values we get the molarity

Molarity =0.5×1000/500=1M

Thus, the molarity of given solution is 1M.

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4 0
1 year ago
Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
A student has a sample of isopropanol (C3H7OH) that has a mass of 78.6 g. The molar mass of isopropanol is 60.1 g/mol. How many
vivado [14]
78.6 g (1mol/60.1 g)= 1.31 moles of isopropanol
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