6(4x + 2) = 3(8x + 4)
Reorder the terms:
6(2 + 4x) = 3(8x + 4)
(2 * 6 + 4x * 6) = 3(8x + 4)
(12 + 24x) = 3(8x + 4)
Reorder the terms:
12 + 24x = 3(4 + 8x)
12 + 24x = (4 * 3 + 8x * 3)
12 + 24x = (12 + 24x)
Add '-12' to each side of the equation.
12 + -12 + 24x = 12 + -12 + 24x
Combine like terms: 12 + -12 = 0
0 + 24x = 12 + -12 + 24x
24x = 12 + -12 + 24x
Combine like terms: 12 + -12 = 0
24x = 0 + 24x
24x = 24x
Add '-24x' to each side of the equation.
24x + -24x = 24x + -24x
Combine like terms: 24x + -24x = 0
0 = 24x + -24x
Combine like terms: 24x + -24x = 0
0 = 0
Solving
0 = 0
Answer: here
Step-by-step explanation:riangles QST and RST are similar. Therefore, the following is true:
q s
--- = ---- This results in 10q=rs.
r 10
Also, since RST is a right triangle, 4^2 + s^2 = q^2.
Since QST is also a right triangle, s^2 + 10^2 = r^2.
4 s
Also: ---- = ----- which leads to s^2 = 40
s 10
Because of this, 4^2 + s^2 = q^2 becomes 16 + 40 = 56 = q^2
Then q = sqrt(56) = sqrt(4)*sqrt(14) = 2*sqrt(14) (answer)
hope it helps
Answer:
x=4, MN= 37, LM= 37, y=7.
Step-by-step explanation:
If MP is a perpendicular bisector to LN, then NP and LP are equivalent.
(Solve for y)
2y+2= 16
(Move the +2 to the right side of the equation)
2y= 14
(Divide both sides by 2 to isolate the variable)
y=7
To find x and the measure of MN and LM, solve for x in the following equation:
7x+9 = 11x-7
(Move 7x to the right side of the equation)
9 = 4x-7
(Move -7 to the right side of the equation.)
16= 4x
(Divide both sides by 4 to isolate the variable.)
4= x
Plug x back into both equations to get the measure of MN and ML
MN=7(4)+9
MN= 28+9
MN= 37
LM= 11(4)-7
LM= 44-7
LM= 37
I hope this helps!
21/25 first you would do 84/100 then you would simplify
We are given the following expression:
![\sqrt[3]{875}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B875%7D)
We can factor 875 as:
![\sqrt[3]{125\times7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%5Ctimes7%7D)
Now we will use the following property:
![\sqrt[x]{a\times b}=\sqrt[x]{a}\times\sqrt[x]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bx%5D%7Ba%5Ctimes%20b%7D%3D%5Csqrt%5Bx%5D%7Ba%7D%5Ctimes%5Csqrt%5Bx%5D%7Bb%7D)
Applying the property:
![\sqrt[3]{125}\times\sqrt[3]{7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%5Ctimes%5Csqrt%5B3%5D%7B7%7D)
Solving the cubic root on the left:
![5\sqrt[3]{7}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B7%7D)
Since we get simplify any further this is the answer.
