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belka [17]
2 years ago
10

Which layer is the oldest layer? PLEASE ANSWER

Chemistry
1 answer:
exis [7]2 years ago
7 0

Answer:

rock strata farthest from the ground surface are the oldest

THERE U GO

<h3>I HOPE IT HELPS YOU </h3>

<h2>PLEASE MARK ME BRAINLIEST IF YOU ARE SATISFIED BY THE ANSWER:)</h2>
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How does the displacement moved affect the amount of work done?
Sholpan [36]

The displacement affect the amount of work done by the fact that more displacement implies more work.

Option B

<u>Explanation:</u>

Work can be defined as the "measure of energy transfer" that occurs when an object is moved over a distance by an external force which is applied in the "direction of the displacement".

Work can be formulated as,

W = (F \times s)\  N / m \\ \\Work = ( Force \times Displacement )\   Newton/meter

From the above-mentioned formula, we can infer that Work is directly proportional to the displacement of the object.Therefore, more the work is more will be its displacement.

6 0
3 years ago
Be sure to answer all parts. Calculate the pH of the following two buffer solutions: (a) 1.4 M CH3COONa/1.6 M CH3COOH. (b) 0.1 M
aalyn [17]

Answer:

a) pH = 4.68 (more effective)

b) pH =4.44.

Explanation:

The pH of buffer solution is obtained by Henderson Hassalbalch's equation.

The equation is:

pH =pKa +log\frac{[salt]}{[acid]}

a) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 1.4 M

[acid] = [CH₃COOH] = 1.6 M

pH = 4.74 + log \frac{1.4}{1.6}= 4.68

This is more effective as there is very less difference in the concentration of salt and acid.

b) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 0.1 M

[acid] = [CH₃COOH] = 0.2 M

pH = 4.74 + log \frac{0.1}{0.2}= 4.44

3 0
3 years ago
Is h3co3 a strong base
tamaranim1 [39]
I read and said it's a weak base
3 0
3 years ago
Which of the following statements does not describe the structure of an atom?  An atom has a small, dense center called the nucl
Gala2k [10]
<span>Inside the nucleus of an atom are protons and electrons. </span>
5 0
3 years ago
Read 2 more answers
How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?
RoseWind [281]
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced</span>
8 0
3 years ago
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