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3 years ago

7

What process is the method by which a neutral object obtains an electrical charge? A) convection B) discharge C) induction D) ra

diation

2 answers:

serg [7]3 years ago

5 0

the answer chose is c; induction

Afina-wow [57]3 years ago

3 0

The answer is C.) induction

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If the volume occupied by 0.500 mol of nitrogen gas at 0°C is 11.2 L, then the volume occupied by 2.00 mol of nitrogen gas at th

kiruha [24]

The volume occupied by 2.00 moles of nitrogen gas at the same temperature and pressure will be

0.500 moles = 11.2 Liters
what about 2 moles =? liters

by cross multiplication

= 11.2 liters x 2moles/ 0.500 moles = 44.8 liters

8 0

3 years ago

Which elements on the periodic table fulfill the octet rule

horsena [70]

Answer:

Noble Gases

Explanation:

The Noble Gases have a full valence shell of 8 electrons. They are stable in that sense.

8 0

3 years ago

X2o3 express you answer as a whole number

kobusy [5.1K]

<span>2.40 - 1.68 =0.72 g of oxigen
moles = 0.72/16 g/mol=0.045

moles x = 1.68/ 55.9=0.03

0.03/0.03 = 1 = x
0.045 / 0.03 = 1.5 = O

to get whole numbers multiply by 2

x2O3

X2O3 +3 CO = 2 X + 3 CO2</span>

4 0

4 years ago

If an atom contains 12 protons and 10 neutrons, what's its mass number?

user100 [1]

A = Z + n

A = 12 + 10

A = 22

Answer C

hope this helps!

7 0

3 years ago

If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te

attashe74 [19]

Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
$pV=nRT$
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
$\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}$

If the supported load is W kg, then
$p_{1} = \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} = 20.3718W \, Pa$
Similarly,
$p_{2} = \frac{4W}{\pi d_{2}^{2}} \, Pa$

$\frac{p_{1}}{p_{2}} = \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}$

Because p₁/p₂ = T₁/T₂, therefore
$16d_{2}^{2} = \frac{293}{423} \\\\ d_{2}^{2} = \frac{0.6927}{16} \\\\ d_{2} = 0.2081 \, m$

The minimum piston diameter at 150 C is 20.8 cm.

Answer: 20.8 cm diameter

8 0

3 years ago