You can use the formula M1 x V1 = M2 x V2 where M1 is the molarity of the first substance and V1 is the volume of the substance. M2 is the molarity of the 2nd substance and V2 is the volume of the substance
if substance 1 is HCl and 2 is KOH we can set up the following equation
x moles / liter (unknown) x .02 liters = .5 moles/ liter x .032 liters
x moles / liter x .02 liters = .016 moles
x moles / liter = .016/.02 liters
x moles / liter = .8 moles/ liter
You have . 8M HCL
Answer:
4477381.7 calories/pound
Explanation:
It is given that,
When a candle burns it produced 41,300 Joules per 1 gram.
We need to convert it into calories per pound.
We know that,
1 cal = 4.184 J
⇒ 1 J = (1/4.184) cal
1 pound = 453.592 grams
⇒1 g = (1/453.592) pounds
Now,
Hence, 41,300 Joules/gram = 4477381.7 calories/pound.
Both the increase in the boling point and the depression on the freezing point are colliative properties.
This is, they are proportional to the number of particles dissolved in the solvent, which is measured by the molality of the solution and the factor i (Van'f Hoff).
The answer to the question is that 1) the boling point of a solution of water and calcium chloride at standard pressure will be higher than the normal boiling point of pure water, and 2) the freezing point of a solution of water and calcium chloride at standard pressure will be lower than the normal freezing point of pure water.
The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels. Protons have a positive charge,neutrons have no charge, and electrons have a negative charge. A neutral atom contains equal numbers of protons and electrons.
