State the period and group to which aluminum belongs to in the periodic table

Consider the reaction when aqueous solutions of potassium hydroxide and ammonium nitrate are combined. The net ionic equation fo

Reil [10]

Answer: $OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)$

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

$KOH(aq)+NH_4NO_3(aq)\rightarrow KNO_3(aq)+NH_3(g)+H_2O(l)$

The equation can be written in terms of ions as:

$K^+(aq)+OH^-(aq)+NH_4^+(aq)+NO_3^-(aq)\rightarrow K^+(aq)+NO_3^-(aq)+NH_3(g)+H_2O(l)$

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The ions which are present on both the sides of the equation are potassium and nitrate ions and hence are not involved in net ionic equation.

Hence, the net ionic equation is :

$OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)$

6 0

3 years ago

a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine

iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction $\frac{a}{b}$

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

$\frac{15.39 g of gold}{2.77 g of chlorine}$

The proportion is the equal relationship that exists between two reasons and is represented by: $\frac{a}{b}=\frac{c}{d}$

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

$\frac{15.39 g of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}$

Solving for the mass of gold gives:

$mass of gold=1 g of chlorine*\frac{15.39 g of gold}{2.77 g of chlorine}$

mass of gold= 5.56 grams

So, there is 5.56 g of gold for every 1 g of chlorine

5 0

3 years ago

The balanced equation below represents the decomposition of potassium chlorate.

dezoksy [38]

The oxidation number of chlorine in the reactant can be determined by K ion and O ion. K ion is +1 and O ion is -2. And the Cl is +5. The gas has the greatest entropy and the solid has the least. In the production, there are solid and gas. So it has more entropy than the reactants with solid only.

6 0

3 years ago

MARKING BRAINLEIST!!

anastassius [24]

Answer:

B: They are the results of many experiments over a long period of time.

Explanation:

4 0

2 years ago

Read 2 more answers

A student is shown a simple model of particles that make up a liquid,as shown.

trapecia [35]

Answer:
Option-D : Decrease the velocities of the particles, and decrease the space between the particles.

Explanation:
The solid state of matter is composed of particles closely packed with a minimum space between them. This closed packing of particles occur due to strong interatomic or intermolecular interactions between particles. Therefore, solids particles have zero translational and rotational motions and only show vibrational motions. So, decrease in velocity and decrease in space between particles is the right answer for making solids.

6 0

3 years ago

State the period and group to which aluminum belongs to in the periodic table ​

State the period and group to which aluminum belongs to in the periodic table