All categories

3 years ago

Which type of energy in the bungee cord prevents the bungee jumper from hitting the ground

Chemistry

1 answer:

Effectus [21]3 years ago

7 0

Elastic potential energy

You might be interested in

Four grams of hydrogen react completely with 32 grams of oxygen. Based on the law of conservation of mass how many grams of wate

neonofarm [45]

Se producirán 36 gramos de agua

Explicación: Ya que en una reacción química no puede descubrir ningún cambio en masa total de las sustancias que en ella intervienen, pues en una reacción química ni se gana ni se pierde masa.

8 0

3 years ago

WORTH 10 POINTS!! Strawberry plants produce offspring through asexual reproduction. Which statement is true about strawberry pla

melomori [17]

Answer:

They are the same as one parent :)

Explanation: that is why we have more yellow corn than black corn because people planted only yellow corn to make more yellow corn :D

6 0

2 years ago

The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = $\frac{0.570 g}{122.12 g/mol}=0.004667 mol$

Energy released by 0.004667 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

$Q=C\times \Delta T$

$15,066.8 J=C\times 2.053^oC$

$C=7,338.92 J/^oC$

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = $\frac{2.900 g}{180.16 g/mol}=0.016097 mol$

Energy released by the 0.016097 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$44,749.1 J=7,338.92 J/^oC\times \Delta T'$

$\Delta T'=6.097^oC$

The temperature change from the combustion of the glucose is 6.097°C.

6 0

3 years ago

I will give brainlyst for this so pls help

omeli [17]

Answer:

Answer -b

Explanation:

Brainliest pls

8 0

3 years ago

Read 2 more answers

What are accounts for physical properties?

Nezavi [6.7K]

Freezing point, boiling point, melting point, smell, attraction or repulsion to magnets, colour change, and many more examples.

3 0

3 years ago