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Anon25 [30]
3 years ago
6

Which of the following is not the same as 2.97 milligrams? 0.0000297 kg, 0.00297 g, 0.297 ch

Chemistry
2 answers:
Travka [436]3 years ago
4 0

the correct answer its  0.002975

erica [24]3 years ago
3 0
<h2>Answer:</h2>

              0.0000297 Kg is not the same as 2.97 mg.

<h2>Proof:</h2>

<u>Converting 2.97 mg into Kg:</u>

As,

                             1 mg is equal to  =  1.0 × 10⁻⁶ Kg

So,

                        2.97 mg will be equal to  =  X Kg

Solving for X,

                      X =  (2.97 mg × 1.0 × 10⁻⁶ Kg) ÷ 1 mg

                      X =  2.97 × 10⁻⁶ Kg

Or,

                      X =  0.00000297 Kg

Hence, 0.0000297 Kg is not the same.

<u>Converting 2.97 mg into g:</u>

As,

                             1 mg is equal to  =  0.001 g

So,

                        2.97 mg will be equal to  =  X g

Solving for X,

                      X =  (2.97 mg × 0.001 g) ÷ 1 mg

                      X =  0.00297 g

Hence, 0.00297 g is the same.

<u>Converting 2.97 mg into cg:</u>

As,

                             1 mg is equal to  =  0.10 cg

So,

                        2.97 mg will be equal to  =  X cg

Solving for X,

                      X =  (2.97 mg × 0.10 cg) ÷ 1 mg

                      X =  0.297 cg

Hence, 0.297 cg is the same.

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Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith
alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
  • Molar mass of isotope A (Li6) = 6.02 u
  • Molar mass of isotope B (Li7) = 7.02 u
  • Atomic mass of lithium = 6.94 u
  • Abundance of A = A%
  • Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

  • Abundance of A (Li6) = 8%
  • Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

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