The +3 charge more common than +2 charge for transition metals in the Fe group. What accounts for this trend?
1 answer:
You might be interested in
<u>Answer:</u> The concentration of required will be 0.285 M.
<u>Explanation:</u>
To calculate the molarity of , we use the equation:
Moles of = 0.016 moles
Volume of solution = 1 L
Putting values in above equation, we get:
For the given chemical equations:
Net equation:
To calculate the equilibrium constant, K for above equation, we get:
The expression for equilibrium constant of above equation is:
As, is a solid, so its activity is taken as 1 and so for
We are given:
Putting values in above equations, we get:
Hence, the concentration of required will be 0.285 M.
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa
∴ on rearranging above eq., we get V2 =
∴ V2 = 4 m3
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa
∴ on rearranging above eq., we get V2 =
∴ V2 = 4 m3