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Novosadov [1.4K]
2 years ago
12

In the equation 3+4x=6x-2 , which can be a first step in solving for x

Mathematics
2 answers:
ICE Princess25 [194]2 years ago
8 0
Subtracting 3 on both sides
Phoenix [80]2 years ago
3 0

adding 2 on both sides....maybe

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Equation of a line with slip of 5 passing through points (-4,-6)
kirill [66]

\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=5[x-(-4)] \\\\\\ y+6=5(x+4)\implies y+6=5x+4\implies y=5x-2

5 0
3 years ago
PLEASEE HEEELPPPP!!!
koban [17]
Practice proportionality. A 50 difference between 100 and 150 is less relevant than 50 in 25 and 75. Its like you have 1 billion dollars and i give you 10 dollars. Its worthless right? What if you have 20 dollars and i give you again 10 dollars, its half of what you have. See the difference? Same number but different value.
4 0
3 years ago
12.93 is what percent of 172.40?
Maurinko [17]

Answer:

<h2>7.5%</h2>

Step-by-step explanation:

METHOD\ 1:\\\\\begin{array}{ccc}172.4&-&100\%\\12.93&-&p\%\end{array}\qquad\text{cross multiply}\\\\172.4p=(12.93)(100)\\\\172.4p=1293\qquad\text{divide both sides by 172.4}\\\\p=7.5\ (\%)

METHOD\ 2:\\\\\dfrac{12.93}{172.4}\cdot100\%=\dfrac{1293}{17240}\cdot100\%=0.075\cdot100\%=7.5\%

6 0
3 years ago
Read 2 more answers
Factor x2+12x+35 , I appreciate all the kind generous help I can receive
stellarik [79]
So, to factor out the equation x²+12x+35, first multiply the first and last numbers.
1×35=35
So, you need to find the multiples of 35 that add up to 12.
So, you find 7 and 5. These two numbers are the magic numbers that will be used as the correct factored form of x²+12x+35, because:
>7×5=35
>7+5=12
So, using these two numbers, you get your factored form as:
(x+5)(x+7)
8 0
3 years ago
Solve in radians help plz
PIT_PIT [208]
I think we can use the identity  sin x/2  = sqrt [(1 - cos x) /2]

cos x -  sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1

cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) =  cos x - 1   Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1

cos^2 x - 0.5 cos x - 0.5 = 0 

cos x = 1 , -0.5

giving x = 0 , 2pi, 2pi/3,  4pi/3  ( for  0  =< x <= 2pi)

because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.

The last 2 results dont fit so the answer is  x = 0 , 2pi Answer
5 0
3 years ago
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