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DENIUS [597]
2 years ago
12

40 . For the first ionization energy for an N2 molecule, what molecular orbital is the electron removed from

Chemistry
1 answer:
DanielleElmas [232]2 years ago
5 0

Answer:

For the first ionization energy for an N2 molecule, the molecular orbital that the electron is removed from is the p orbital.

It should be noted that valence electrons simply refer to the electrons in an atom that holds the last orbital that is required for chemical bonding with other elements.

The existence of valence electrons can define the chemical properties of that atom. For the first energy in ionization of an N2 molecule, the molecular orbital where the electron could be extracted is the p orbital since it has the highest energy level.

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Answer:

It should be polarity

8 0
3 years ago
What is the volume of 68.0 g of ether if the density of ether is 0.72 g/mL?
umka2103 [35]

Answer:

94.44

Explanation:

Volume is equal to Mass/Density so therefore, you do the mass which is 68.0 g/0.72 g/mL which is the density and get 94.44 mL because the g cancel each other out when it comes to the label!

3 0
3 years ago
Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. what volume of hydrogen chloride
Anna71 [15]
The reaction between methane gas and chlorine gas to form hydrogen chloride and carbon tetrachloride, all in their gaseous form can be expressed through the chemical reaction below.

        CH₄ + 4Cl₂ --> 4HCl + CCl₄

Let us assume that all the involved gases behaves ideally such that each mole of the gas is equal to 22.4 L. 

Through proper dimensional analysis, the volume of the produced hydrogen chloride is calculated,
    V(HCl) = (1.69 mL CH₄)(1 L CH₄/ 1000 mL CH₄)(1 mol CH₄/22.4 L CH₄)(4 mols HCl/1 mol CH₄)(22.4 L HCl/1 mol HCl)(1000 mL/1 L)
    

    V(HCl) = 6.76 mL

<em>ANSWER: 6.76 mL</em>


3 0
3 years ago
The air that we breathe is actually a mixture of several gases. of those involved, which is the third most abundant component of
labwork [276]
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4 0
3 years ago
An ideal gas is allowed to expand from 5.40 L to 35.1 L at constant temperature. By what factor does the volume increase?
horrorfan [7]

Answer:

a) 6.5

b) pressure decreases

c)22 atm

Explanation:

Since the initial volume V1 is 5.40 L and the final volume V2 is 35.1 L, the ratio of V2:V1= 35.1/5.40= 6.5 hence the volume increases by a factor of 6.5.

When the volume increases, the pressure decreases accordingly in accordance with Boyle's law. Boyle's law states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

c) From Boyle's law

Initial volume V1= 5.40 L

Final volume V2= 35.1 L

Initial pressure P1= 143 ATM

Final pressure P2 = the unknown

P1V1= P2V2

P2= P1V1/V2

P2 = 143 × 5.40/ 35.1

P2= 22 atm

6 0
3 years ago
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