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prisoha [69]
3 years ago
14

Which phrase best describes electronegativity?(1 point)

Chemistry
2 answers:
frez [133]3 years ago
6 0

Answer:

ELECTRONEGATIVITY is the tendency of an atom in the molecule to attract the bonded pair of electrons .

Explanation:

it might help you!!!!!!

amm18123 years ago
5 0

Answer:

the relative strength with which an element attracts electrons in a chemical bond

Explanation:

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Sulfur trioxide is a gas that reacts with liquid water to produce aqueous sulfuric Acid or acid rain what is the equation for th
bearhunter [10]

Answer:

SO₃(g) + H₂O(l) → H₂SO₄(aq)

Explanation:

The<em> molecular formula for the involved species</em> are:

  • Sulfur trioxide = SO₃. ("trioxide" indicates the presence of 3 oxygen atoms).
  • Water = H₂O
  • Sulfuric acid = H₂SO₄

With the above information in mind we can proceed to write the reaction equation:

  • SO₃(g) + H₂O(l) → H₂SO₄(aq)
5 0
3 years ago
What is the temperature shown on the thermometer below?
vaieri [72.5K]

Answer:

- 13 * c

Explanation:

hope it helps u.....

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3 years ago
Tierra is playing in her backyard when she hears her friend calling out to her. She can't see her friend but can hear her friend
mixer [17]

Answer:

diffraction

Explanation:

the correct answer is diffraction

4 0
3 years ago
Read 2 more answers
7.The _____ theory of matter states that all particles of matter are in constant motion.
SashulF [63]
The kinetic energy theory of matter states that all particles of matter are in constant motion.
Kinetics has to do with some kind of movement, which is why this answer is the only plausible one. 
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3 years ago
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A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression o
Ludmilka [50]

Answer:

0.297 °C

Step-by-step explanation:

The formula for the <em>freezing point depression </em>ΔT_f is

ΔT_f = iK_f·b

i is the van’t Hoff factor: the number of moles of particles you get from a solute.

For glucose,

       glucose(s) ⟶ glucose(aq)

1 mole glucose ⟶ 1 mol particles     i = 1

Data:

Mass of glucose = 10.20 g

  Mass of water = 355 g

                 ΔT_f = 1.86 °C·kg·mol⁻¹

Calculations:

(a) <em>Moles of glucose </em>

n = 10.20 g × (1 mol/180.16 g)

  = 0.056 62 mol

(b) <em>Kilograms of water </em>

m = 355 g × (1 kg/1000 g)

   = 0.355 kg

(c) <em>Molal concentration </em>

b = moles of solute/kilograms of solvent

  = 0.056 62 mol/0.355 kg

  = 0.1595 mol·kg⁻¹

(d) <em>Freezing point depression </em>

ΔT_f = 1 × 1.86 × 0.1595

        = 0.297 °C

3 0
3 years ago
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