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Advocard [28]
2 years ago
12

A 1500 kg car is moving at 15m/s what is the impulse experienced by the car

Physics
2 answers:
denpristay [2]2 years ago
7 0

Answer:

22500 Ns

Explanation:

Given,

Mass ( m ) = 1500 kg

Velocity ( v ) = 15 m/s

Formula : -

Impulse = mv

Impulse

= 1500 x 15

= 22500 Ns

Therefore,

22500 Ns is the impulse experienced by the car.

Note : -

Ns is the unit of impulse.

Sindrei [870]2 years ago
3 0
Impulse= mass x velocity so answer is 22500
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All of the following equations are statements of the ideal gas law except
elena55 [62]

Answer:

a. P = nRTV

Explanation:

The question is incomplete. Here is the complete question.

"All of the following equations are statements of the ideal gas law except a. P = nRTV b. PV/T = nR c. P/n = RT/v d. R = PV/nT"

Ideal gas equation is an equation that describes the nature of an ideal gas. The molecule of an ideal gas moves at a particular velocity depending on the temperature. This gases collides with one another elastically. The collision that an ideal gas experience is a perfectly elastic collision.

The ideal gas equation is expressed as shown:

PV = nRT where:

P is the pressure of the gas

V is the volume

n is the number of moles

R is the ideal gas constant

T is the temperature.

Based on the formula given for an ideal gas, it can be inferred that the equation. P = nRTV is not a statement of an ideal gas equation.

The remaining option will results to an ideal gas equation if they are cross multipled.

7 0
4 years ago
A satellite of mass m is in a circular orbit of radius R2 around a spherical planet of radius R1 made of a material with density
Amiraneli [1.4K]

Answer:

a)      K = 2/3 π G m ρ R₁³ / R₂ ,  b) U = - G m M / r

Explanation:

The law of universal gravitation is

     F = G m M / r²

Part A

Let's use Newton's second law

     F = m a

The acceleration is centripetal

     a = v² / R₂

     

      G m M / R₂² = m v² / R₂

      v² = G M / R₂

They give us the density of the planet

    ρ = M / V

    V = 4/3 π R₁³

    M =   ρ V

    M =   ρ 4/3 π R₁³

    v² = 4/3 π G  ρ R₁³ / R₂

    K = ½ m v²

    K = ½ m (4/3 π G ρ R₁³ / R₂)

    K = 2/3 π G m ρ R₁³ / R₂

Part B

Potential energy and strength are related

     F = - dU / dr

     ∫ dU = - ∫ F. dr

The force was directed towards the center and the vector r outwards therefore there is an angle of 180º between the two cos 180 = -1

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    U - U₀ = G m M (- r⁻¹)

We evaluate for

    U - U₀ = -G m M (1 / r_{f} -  1 /r_{i})

They indicate that for ri = ∞     U₀ = 0

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6 0
3 years ago
Partially correct answer iconYour answer is partially correct. A proton initially has and then 2.30 s later has (in meters per s
morpeh [17]

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Sholpan [36]
The best and most correct answer among the choices provided by the question is the second choice "Lake Michigan"


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I hope my answer has come to your help. God bless and have a nice day ahead!
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3 years ago
Which example would most likely decrease friction?
andreev551 [17]

Answer:

using cleats other than gym shoes

Explanation:

the cleats hwve spikes and help gain speed

7 0
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