Charge on a capacitor = (capacitance) x (voltage)
7.68 Coulomb = (capacitance) x (9.0 V)
Capacitance = (7.68 Coul) / (9.0 V)
<em>Capacitance = 0.83 Farad</em>
<em></em>
Apparently, the " 10^something " after the 7.68 C got lost.
If the charge is actually 7.68 <u>micro</u>coulombs, then the answer is<em> (A) .</em>
Answer:
c. same momentum
Explanation:
got it correct on edge2020
Answer:
Final Velocity = √(eV/m)
Explanation:
The Workdone, W, in accelerating a charge, 2e, through a potential difference, V is given as a product of the charge and the potential difference
W = (2e) × V = 2eV
And this work is equal to change in kinetic energy
W = Δ(kinetic energy) = ΔK.E
But since the charge starts from rest, initial velocity = 0 and initial kinetic energy = 0
ΔK.E = ½ × (mass) × (final velocity)²
(Velocity)² = (2×ΔK.E)/(mass)
Velocity = √[(2×ΔK.E)/(mass)]
ΔK.E = W = 2eV
mass = 4m
Final Velocity = √[(2×W)/(4m)]
Final Velocity = √[(2×2eV)/4m]
Final Velocity = √(4eV/4m)
Final Velocity = √(eV/m)
Hope this Helps!!!
Answer:
D air
Explanation:
it is not found on the periodic table
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