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igor_vitrenko [27]
3 years ago
12

Can somebody help me pls

Physics
1 answer:
gladu [14]3 years ago
7 0

Answer:

B

Explanation:

sound wave is a longitudinal wave and constant frequency is given.

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In a cyclic process, a gas performs 123 J of work on its surroundings per cycle. What amount of heat, if any, transfers into or
Margaret [11]

Answer:

123 J transfer into the gas

Explanation:

Here we know that 123 J work is done by the gas on its surrounding

So here gas is doing work against external forces

Now for cyclic process we know that

\Delta U = 0

so from 1st law of thermodynamics we have

dQ = W + \Delta U

dQ = W

so work done is same as the heat supplied to the system

So correct answer is

123 J transfer into the gas

8 0
3 years ago
A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca
viva [34]

Answer:

a=0.2*10^{-5}g

Explanation:

From the question we are told that:

Mass M=180=>0.18kg

Charge Q=18mC=18*10^-^3C

Velocity v=2.2m/s

Length of Wire L=8.6cm=>0.086

Current I=30A

Generally the equation for Magnetic Field of Wire B is mathematically given by

 B=\frac{\mu_0*I}{2\pi*l}

 B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}

 B=6.978*10^{-5}T

Generally the equation for Force on the plane F is mathematically given by

 F=qvB

Therefore

 ma=qvB

 a=\frac{qvB}{m}

 a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}

 a=2.37*10^{-5}

Therefore in Terms of g's

 a=\frac{2.37*10^{-5}}{9.8}

 a=0.2*10^{-5}g

8 0
2 years ago
If your average speed is 3 m/s, how far have you traveled in 1 second, 2 second, 3 seconds?
vichka [17]

Answer:

in 1 second 3m, in 2 seconds 6m, in 3 seconds 9m.

Explanation:

distance=speed × time

4 0
3 years ago
Read 2 more answers
A sound wave has a frequency of 500 Hz and a wavelength of 1.8 m. What is the wave speed of the sound wave? Question 1 options:
antoniya [11.8K]

Answer:

The wave speed of the sound wave is 900 \frac{m}{s}.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The propagation velocity is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. Relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation: v = f * λ.

In this case:

  • f= 500 Hz
  • λ= 1.8 m

Replacing:

v= 500 Hz* 1.8 m

v= 900 \frac{m}{s}

<u><em>The wave speed of the sound wave is 900 </em></u>\frac{m}{s}<u><em>.</em></u>

7 0
3 years ago
A particle with a charge of − 5.10 nC is moving in a uniform magnetic field of B⃗ =−( 1.20 T )k^. The magnetic force on the part
marta [7]

Answer:

Explanation:

Given that,

Charge q=-5.10nC

Magnetic field B= -1.2T k

And the magnetic force

F =−( 3.30×10−7N )i+( 7.60×10−7N )j

Let the velocity be V(xi + yj + zk)

Then, the force is given as

Note i×i=j×j×k×k=0

i×j=k. j×i=-k

j×k=i. k×j=-i

k×i=j. i×k=-j

F= q(v×B)

−( 3.30×10−7N )i+( 7.60×10−7N )j =

q(xi + yj + zk) × -1.2k

−( 3.30×10−7N )i+( 7.60×10−7N )j=

q( -1.2x i×k - 1.2y j×k - 1.2z k×k)

−( 3.30×10−7N )i+( 7.60×10−7N )j=

q( 1.2xj - 1.2y i )

−( 3.30×10−7N )i+( 7.60×10−7N )j=

q( -1.2y i + 1.2x j)

So comparing comparing coefficients

let compare x axis component

-( 3.30×10−7N )i=-1.2qy i

−3.30×10−7N = -1.2qy

y= -3.3×10^-7/-1.2q

y= -3.3×10^-7/-1.2×-5.10×10^-9)

y=-53.92m/s

Let compare y-axisaxis

7.6×10−7N j = 1.2qx j

7.6×10−7N = 1.2qx

x= 7.6×10^-7/-1.2q

x= 7.6×10^-7/1.2×-5.10×10^-9)

x=-124.18m/s

a. Then, the velocity of the x component is x= -124.18m/s

b. Also, the velocity component of the y axis is =-53.92m/s

c. We will compute

V•F

V=-124.18i -53.92j

F=−( 3.30×10−7 N )i+( 7.60×10−7 N )j

Note

i.j=j.i=0. Also i.i = j.j =1

V•F is

(-124.18i-53.92j)•−(3.30×10−7N)i+(7.60×10−7 N )j =

4.1×10^-5 - 4.1×10^-5=0

V•F=0

d. Angle between V and F

V•F=|V||F|Cosx

0=|V||F|Cos

Cosx=0

x= arccos(0)

x=90°

Since the dot product is zero, from vectors , if the dot product of two vectors is zero, then the vectors are perpendicular to each other

6 0
3 years ago
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