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Arisa [49]
3 years ago
9

A plant blossoms with violet-colored flowers. The flowers appear violet because they absorb all light rays except for____ rays.

Physics
2 answers:
mamaluj [8]3 years ago
8 0

A plant blossoms with violet-colored flowers. The flowers appear violet because they <u>absorb</u> all light rays except for <u>violet</u> rays.

jolli1 [7]3 years ago
5 0
~Hello there! ^_^

Your question: A plant blossoms with violet-colored flowers. The flowers appear violet because they absorb all light rays except for____ rays.

Your answer: A plant blossoms with violet-colored flowers. The flowers appear violet because they absorb all light rays except for violet rays.


Hope this helps~

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Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal
Anastaziya [24]

The most important characteristics that are exhibited by metals are-

1- Metals are ductile

2-Most metals are conductive in nature.

3-Most metals are malleable.

4- Metals have strong inter molecular force of attraction between the.

5-Metals have luster.

6-Metals are sonorous.

Here we are given Tungsten filament.

Tungsten is  a metal.So it must be conductive and as well as ductile in nature.

The electric filament that we are using in our electric bulb glows due to the heating effect of current.Hence the chosen substances for glowing electric bulb must have high melting point.

The melting point of tungsten is 1650 degree celsius which is very high.That's why it is used in electric bulb.

Hence the correct answer to the question is the third one i.e Tungsten is ductile,has a high melting point, and is electrically conductive.



5 0
3 years ago
Read 2 more answers
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?​
Xelga [282]
<h2><u>Question</u><u>:</u><u>-</u></h2>

Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?

<h2><u>Answer:</u><u>-</u></h2>

<h3>Given,</h3>

=> Force applied by Ryan = 10N

=> Distance covered by the book after applying force = 30 cm

<h3>And,</h3>

30 cm = 0.3 m (distance)

<h3>So,</h3>

=> Work done = Force × Distance

=> 10 × 0.3

=> 3 Joules

\small \boxed{work \: done \:  by \: Ryan \:  = 3 \: Joules}

4 0
3 years ago
3. If I run 150m in 30 seconds, what speed will I have been running at?
Radda [10]

Answer:

speed = distance/time

Explanation:

speed = 150/30

speed =5m/s

you were running fast .....5m/s is a good speed

7 0
2 years ago
The function of a cell depends primarily on its ?
Schach [20]
<span>Organelles which are very important in giving nutrients. During cellular respiration, the food molecules such as glucose, are oxidized to carbon dioxide (CO2) and water (H2O) and trapped in ATP (Adenosine triphosphate) form for further us of cell’s activities. ATP’s are formed at mitochondria – the cell’s powerhouse. This type of organelle takes and breaks nutrients absorbed by the cell and creates energy afterward. The energy from ATP is then used by the body in kinetic activities like running & walking or involuntary activities like breathing, blood circulation, stimulus-responding, etc.</span>
8 0
3 years ago
In this example we will analyze the forces acting on your body as you move in an elevator. Specifically, we will consider the ca
dexar [7]

Answer:

The reading of the scale during the acceleration is 446.94 N

Explanation:

Given;

the reading of the scale when the elevator is at rest = your weight, w = 600 N

downward acceleration the elevator, a = 2.5 m/s²

The reading of the scale can be found by applying Newton's second law of motion;

the reading of the scale  = net force acting on your body

R = mg + m(-a)

The negative sign indicates downward acceleration

R = m(g - a)

where;

R is the reading of the scale which is your apparent weight

m is the mass of your body

g is acceleration due to gravity, = 9.8 m/s²

m = w/g

m = 600 / 9.8

m = 61.225 kg

The reading of the scale is now calculated as;

R = m(g-a)

R = 61.225(9.8 - 2.5)

R = 446.94 N

Therefore, the reading of the scale during the acceleration is 446.94 N

4 0
2 years ago
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