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dsp73
3 years ago
10

Here the file attached

Physics
2 answers:
Zarrin [17]3 years ago
8 0

The <em>first</em> statement is the correct one.  Don't make me type the whole thing out.

Nuetrik [128]3 years ago
7 0

Answer:

A

Explanation:

Amplitude = height of the wave = 1

Wavelength = 3

They are slightly shifted.

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A particular planet has a moment of inertia of 9.74 × 1037 kg ⋅ m2 and a mass of 5.98 × 1024 kg. Based on these values, what is
malfutka [58]

Answer:  A) 6.38(10)^{6} m

Explanation:

The equation for the moment of inertia I of a sphere is:

I=\frac{2}{5}mr^{2} (1)

Where:

I=9.74(10)^{37}kg m^{2} is the moment of inertia of the planet (assumed with the shape of a sphere)

m=5.98(10)^{24}kg is the mass of the planet

r is the radius of the planet

Isolating r from (1):

r=\sqrt{\frac{5I}{2m}} (2)

Solving:

r=\sqrt{\frac{5(9.74(10)^{37}kg m^{2})}{2(5.98(10)^{24}kg)}} (3)

Finally:

r=6381149.077m \approx 6.38(10)^{6} m

Therefore, the correct option is A.

4 0
3 years ago
A train slows down as it pulls into a station. if the train is moving from your left to your right, what are the directions of t
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The directions of the vectors for velocity and acceleration are in the opposite directions.

  • The velocity vector is always in the direction of motion of the object. So, the direction of velocity is in the right from our point of view.
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Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, the directions of the vectors for velocity and acceleration are in the opposite directions.

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3 0
2 years ago
An unknown galaxy has a large flattened core. Which of the following classifications would best fit this galaxy's description? I
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Explanation:

7 0
3 years ago
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Which of the following is not a type of system?
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3 years ago
a container of water is knocked off a 10.0 meter high ledge with a horizontal velocity of 1.00 meters/second. calculate the time
Evgen [1.6K]

Answer:

1.43 s

Explanation:

The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.

The vertical distance covered by an object in free fall is given by

S=ut + \frac{1}{2}at^2

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since u=0, it can be rewritten as

S=\frac{1}{2}gt^2

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t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(10.0 m)}{9.8 m/s^2}}=1.43 s

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