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2 years ago

Again could someone help me on this?

Chemistry

1 answer:

Whitepunk [10]2 years ago

3 0

Answer:

Celsius, Fahrenheit and Kelvin are the three common temperature scales.

Explanation:

Celsius, Fahrenheit and Kelvin are the three common temperature scales.

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Balance the following chemical equation by providing the correct coefficients. CO+H2 ———- H2O+CH4

makvit [3.9K]

Answer:

CO + H2 --> CH4 + H2O

Explanation:

3 0

3 years ago

18. Which two particle diagrams each represent a sample of one substance? Key O = atom of oxygen = atom of hydrogen 0 = atom of

Mars2501 [29]

Answer:

1 and 11

Explanation:

3 0

3 years ago

For each of the processes, determine whether the entropy of the system is increasing or decreasing. The system is underlined.

defon

1. Increasing
2. Increasing
3. Decreasing
4. Increasing
5. Decreasing

6 0

3 years ago

We have air (21% O2 and 79% N2) at 23 bar and 30 C. 4. What is the ideal molar volume (m^3/kmol)? a. b. What is the Z factor? Wh

k0ka [10]

Answer:

The ideal molar volume is $\frac{V}{n} =V_z= 0.001095 \ m^3/mol$

The Z factor is $Z = 0.09997$

The real molar volume is $\frac{V_r}{n} = V_k= 0.0001095\ \frac{m^3}{mol}$

Explanation:

From the question we are told that

The pressure is $P = 23 \ bar = 23 *10^5 Pa$

The temperature is $T = 30 ^ oC = 303 \ K$

According to the ideal gas equation we have that

$PV = nRT$

=> $\frac{V}{n}=V_z= \frac{RT}{P}$

Where $\frac{V}{n }$ is the molar volume and R is the gas constant with value

$R = 8.314 \ m^3 \cdot Pa \cdot K^{-1}\cdot mol^{-1}$

substituting values

$\frac{V}{n} =V_z= \frac{ 8.314 * 303}{23 *10^{5}}$

$\frac{V}{n} =V_z= 0.001095 \ m^3/mol$

The compressibility factor of the gas is mathematically represented as

$Z = \frac{P * V_z}{RT}$

substituting values

$Z = \frac{23 *10^{5} * 0.001095}{8.314 * 303}$

$Z = 0.09997$

Now the real molar volume is evaluated as

$\frac{V_r}{n} = V_k= \frac{Z * RT }{P}$

substituting values

$\frac{V_r}{n} = V_k= \frac{0.09997 * 8.314 * 303}{23 *10^{5}}$

$\frac{V_r}{n} = V_k= 0.0001095\ \frac{m^3}{mol}$

8 0

3 years ago

Who has the greater boiling point C2H6or C2H50H

hichkok12 [17]

Answer:

C2H5OH has a greater boiling point.

Explanation:

It is a bigger molecule than C2H6.

7 0

3 years ago