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erastova [34]
2 years ago
7

In the given figure, O is the centre of a circle, TN is a Tangent, AN = 12 cm and OE = 5 cm. Find the length of NE.​

Mathematics
1 answer:
sp2606 [1]2 years ago
3 0

Answer:

NE = 8 cm

Step-by-step explanation:

Radius OA = OE = 5 cm

In right triangle OAN, OA² + AN² = ON²

5² + 12² = ON²

ON² = 25 + 144 = 169

so ON = 13 cm

NE = ON - OE = 13 - 5 = 8 cm

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Alex73 [517]
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8 0
3 years ago
Solve: 37x + 41y = 70<br>41x + 37y = 86​
AysviL [449]

Step-by-step explanation:

37x + 41y = 70 --- R¹

41x + 37y = 86 --- R²

R¹ + R² : 78x + 78y = 156

78(x + y) = 156

x + y = 2 --- R³

R¹ - R² : -4x + 4y = -16

4(y - x) = -16

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4 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
wlad13 [49]

Answer:

\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}

Step-by-step explanation:

To solve the question we refresh our knowledge of the quotient rule.

For a function f(x) express as a ratio of another functions u(x) and v(x) i.e

f(x)=\frac{u(x)}{v(x)}\\, the derivative is express as

\frac{df(x)}{dx}=\frac{v(x)\frac{du(x)}{dx}-u(x)\frac{dv(x)}{dx}}{v(x)^{2} }

from y=lnx/x^{2}

we assign u(x)=lnx and v(x)=x^2

and the derivatives

\frac{du(x)}{dx}=\frac{1}{x}\\\frac{dv(x)}{dx}=2x\\.

Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e y=lnx\\\frac{dy}{dx}=\frac{1}{x}

If we substitute values into the quotient expression we arrive at

\frac{dy}{dx}=\frac{(x^{2}*\frac{1}{x})-(2x*lnx)}{x^{4}}\\\frac{dy}{dx}=\frac{x-2xlnx}{x^{4}}\\\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}

8 0
3 years ago
Find each indicated product <br>1) 2s(s-4) <br>2) (w+7) (w+3)<br>3) (x+9) (x-2) 4) (2t-1) (t+5)​
Andrej [43]

Answer:

1) 2s(s-4

Ans:

2(−4)

22−8

2)(w+7) (w+3)

Ans:

(+7)(+3)

(+3)+7(+3)

2+3+7(+3)

2+3+7+21

2+10+21

4 0
2 years ago
What is the expression in factored form x^2+13x+42
omeli [17]
The correct answer is (x+6)(x+7). Great job.
8 0
3 years ago
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