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andrezito [222]
2 years ago
14

Which sample would serve as a better buffer and therefore a better environment for aquatic life?

Chemistry
2 answers:
Ann [662]2 years ago
6 0

Answer:

sample A

Explanation:

the first one because of the ppm value

Aleks04 [339]2 years ago
6 0

Explanation:

Buffer solution is that which is made of weak acid .

  • See pH is equal

Solubility decreases with increase in no of drops .

  • Sample B is best buffer
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Alex is 1.67 meters tall. His
nekit [7.7K]

Answer: A

Explanation:

1cm=.01 so it would be 167-34

5 0
3 years ago
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2H2+ O2 —> 2H2 O
lukranit [14]

Answer:bubuvuvuvftctcrchj

Explanation:

8 0
3 years ago
A 0.708 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
ollegr [7]

Answer:

The metal has a molar mass of 65.37 g/mol

Explanation:

Step 1: Data given

Mass of the metal = 0.708 grams

Volume of hydrogen = 275 mL = 0.275 L

Atmospheric pressure = 1.0079 bar = 0.9947 atm

Temperature = 25°C

Vapor pressure of water at 25 °C = 0.03167 bar = 0.03126 atm

Step 2: The balanced equation

M(s) + H2SO4(aq) ⟶ MSO4 (aq) + H2(g)

Step 3: Calculate pH2

Atmospheric pressure = vapor pressure of water + pressure of H2

0.9947 atm = 0.03126 atm + pressure of H2

Pressure of H2 = 0.9947 - 0.03126

Pressure of H2 = 0.96344 atm

Step 4: Calculate moles of H2

p*V=n*R*T

⇒ with p = The pressure of H2 = 0.96344 atm

⇒ with V = the volume of H2 = 0.275 L

⇒ with n = the number of moles H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 25°C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.96344 * 0.275)/(0.08206*298)

n = 0.01083 moles

Step 5: Calculate moles of M

For 1 mole of H2 produced, we need 1 mole M

For 0.0108 moles of H2 we need 0.01083 moles of M

Step 6: Calculate molar mass of M

Molar mass M = Mass M / moles M

Molar mass M = 0.708 grams / 0.01083 moles

Molar mass M = 65.37 g/mol

The metal has a molar mass of 65.37 g/mol

5 0
3 years ago
describe how a physical property such as mass or Texture can change without causing a change in the substance
Tom [10]

You have to be very careful with this question. A change in mass can also occur in chemical changes especially if you have too much of something. For example

CH4 + 1.5 02 ===> CO2 + H2O

If you have too much of either CH4 or O2, there will be some CH4 or O2 left over. There has been a change in mass that you have too much of.

However that is not the point of the question. It is just something you need to be aware of.

Suppose you have a piece of aluminum and you take a course grinder after it. You will change the texture of the side you took the grinder to. If the aluminum has been anodized (a color has been put on it's surface), you may grind the color off or if it is just plain aluminum, you may roughen the surface, but you won't change what the aluminum will do chemically.

You may need only a small portion of the aluminum and you grind off just what you need. That will change the mass of both what you took off and the piece that you want, but the aluminum will still do whatever chemical property you need to use.

So you can change both texture and mass without changing the chemical properties of the substance whose mass or texture you are changing.

3 0
3 years ago
How many microliters are in 7.4 x 10^-61 centimeters?
schepotkina [342]

Answer:

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Explanation:

SI unit of volume is liter.

1 dm^{3}=1 liter ..............................(1)

1dm=10cm

1dm^{3} = 1000 cm^{3}.................(2)

replacing value of 1 dm^{3}from equation (1) in equation (2)

1 liter = 1000 cm^{3}...................(3)

but

1 liter = 10^{6} microliters....................(4)

replacing value of 1 liter from equation (3) in equation (4)

1000 cm^{3} = 10^{6} microliters

on solving further ,we get

1 cm^{3} = \frac{10^{6}}{10^{3}}microliter

1 cm^{3} = 1000 microliter

7.4\times 10^{-61}\times 1000

Microliters = 7.4\times 10^{-58}

8 0
2 years ago
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