Answer:
a) 10.0 mm
b) 8.7 x 10¹³ times
Explanation:
Atom diameter = 1.06 x 10⁻¹⁰ m ________________ 100%
Nucleus diameter = 2.40 x 10⁻¹⁵ m ______________ x
x = 2.26 x 10⁻³ %
The nucleus diameter is equivalent to 2.26 x 10⁻³ % of the total atom size.
a) The Empire State Building model:
1 ft = 304.8 mm
1454 ft = 443179.2 mm
443179.2 mm______ 100%
y ______ 2.26 x 10⁻³ %
y = 10.0 mm
In this model, the diameter of the nucleus would be 10.0 mm.
b) Sphere volume: V =(4 · π · r³
)/3
V atom = (4 . π .( 0.53x10⁻¹⁰)³ )/3
V atom = 6.2 x 10⁻³¹ m³
V nucleus = (4 . π .( 1.2x10⁻¹⁵)³ )/3
V nucleus = 7.2 x 10⁻⁴⁵ m³
V atom / V nucleus = 6.2 x 10⁻³¹ m³ / 7.2 x 10⁻⁴⁵ m³
V atom / V nucleus = 8.7 x 10¹³
The atom is times 8.7 x 10¹³ larger in volume than its nucleus.
Answer:
mass (g) needed = 710.2 grams Na₂SO₄(s)
Explanation:
Needed is 2.5 Liters of 2.0M Na₂SO₄; formula wt Na₂SO₄ = 142.04g/mol.
mass (grams) of Na₂SO₄(s) = Molarity needed x Volume needed in Liters x Formula Wt of solute
mass (grams) of Na₂SO₄(s) = (2.5L)(2.0M)(142.04g/mol) = 710.2 grams Na₂SO₄(s)
Mixing: Transfer 710.4 grams Na₂SO₄ into mixing vessel and add water-solvent up to but not to exceed 2.5 Liters total volume. Mix until dissolved.
Gives 2.5 Liters of 2.0M Na₂SO₄(aq) solution.
Answer:
It's either Substance 1 or Subatance 4 !
Answer:
4 significant figures
Explanation:
Significant figures are the units/digits within a number that make the number more accurate and precise.
All digits (except for 0) are always significant. Therefore, all the digits in 43.55 are significant. Since there are 4 digits in the given number, there are 4 significant figures.
