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2 years ago

PLEASE HELP WHATS THE ASNWER

Physics

1 answer:

Mice21 [21]2 years ago

4 0

Answer:

Explanation:

Since the room temperature and the water placed in it is the same degrees hence no change

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5. Alex goes cruising on his dirt bike. He rides 700 m north, 300 m east, 400 m north, 600 m west, 1200 m south 300 m east and f

Gala2k [10]

Answer:

Explanation:

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3 years ago

A 600g boulder has a density of 8 g/cm3. What is the volume of the boulder

Amiraneli [1.4K]

Density can be calculated using the following rule:
density = mass / volume

Since the density is given as 8 gm/cm^3 and the mass is given as 600 grams, therefore, all we need to do is substitute in the equation to get the value of the volume as follows:
8 = 600 / volume
volume = 600 / 8 = 75 cm^3

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4 years ago

In astronomy which planet spins slowest on its axis

sertanlavr [38]

Venus - 4 miles per hour

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3 years ago

When white light is incident on a prism, which one of the resulting color components will have the lowest index of refraction?

soldi70 [24.7K]

Blue has the lowest index of refraction

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3 years ago

Read 2 more answers

If it has enough kinetic energy, a molecule at the surface of the Earth can "escape the Earth's gravitation", in the sense that

user100 [1]

Answer:

$K_E=mgr_E$

Explanation:

By conservation of energy, the sum of the kinetic and gravitational potential energies at the surface of the Earth must be equal than their sum at infinity, so we have:

$K_E+U_E=K_\infty+U_\infty$

$\frac{mv_E^2}{2}-\frac{GM_Em}{r_E}=\frac{mv_\infty^2}{2}-\frac{GM_Em}{r_\infty}$

Where $G=6.67\times10^{-11}Nm^2/kg^2$ is the gravitational constant, $M_E=5.97\times10^{24}kg$ and $r_E=6371000m$ are the mass and radius of the Earth, <em>m </em>is the mass of the particle, $v_E$ its velocity at the surface of the Earth (which would be its escape velocity) and $v_\infty$ and $r_\infty$ are the velocities and distance at infinity, which would be null and infinity respectively, so the right hand side of our equation is 0J, which leaves us with:

$\frac{GM_Em}{r_E}=\frac{mv_E^2}{2}=K_E$

Also, since the force the molecule experiments is the force of gravity (disregarding drag), we can write its weight in terms of Newton's Law of Gravitation:

$F=mg=\frac{GM_Em}{r_E^2}$

Which means that:

$\frac{GM_Em}{r_E}=mgr_E$

So finally putting all together we can write:

$K_E=\frac{GM_Em}{r_E}=mgr_E$

4 0

3 years ago