If I remember correctly, it would be B. A very large amount of energy is produced from a tremendous mass.
Answer:
The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance (the decimal associated with percent of atoms of that element that are of a given isotopе). An element does not have an absolute atomic mass.
<em>Hope</em><em> this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Answer: 159 grams
Explanation:
Copper (ii) oxide has the chemical formula CuO.
Now given that:
Mass of CuO in grams = ? (let unknown value be Z)
Number of moles = 2.00 moles
Molar mass of CuO = ?
For the molar mass of CuO: Atomic mass of Copper = 63.5g ; Oxygen = 16g
= 63.5g + 16g
= 79.5 g/mol
Apply the formula:
Number of molecules = (mass in grams/molar mass)
2.00 moles = (Z / 79.5 g/mol)
Z = 79.5 g/mol x 2.00 moles
Z = 159g
Thus, there are 159 grams in 2.00 moles of copper (ii) oxide
Answer:
D. A federal government agency publishes an article in a professional scientific journal detailing technical details of a new virus.
Explanation:
Public scientific communication is a way used by scientists to make the audience able to understand the basics of science to communicate an informed decision. There are several skills under public scientific communication that include connect with the public, talk to journalists, make science understandable, and understand the audience.
<u>The best way to connect with the audience is to publish an article in a professional scientific journal because mostly journals are peer-reviewed having standard of quality.</u>
A federal government agency informing about a new virus through an article in a professional scientific journal is the best way of public scientific communication as it will be for a specific audience along with a standard of quality.
Hence, the correct answer is "D".
Answer:
1.16L can be made
Explanation:
Molarity = Mol / Volume
Volume = Mol / Molarity
Let's determine the moles of salt, with that mass:
130 g FeCl₂ . 1mol / 126.75 g = 1.02 moles of FeCl₂
Volume = 1.02 mol / 0.88 mol/L → 1.16L
