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2 years ago

What is faradays first law

Chemistry

1 answer:

svetlana [45]2 years ago

3 0

Answer:

“Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced. Likewise, if the conductor circuit is closed, a current is induced, which is called induced current.”

Explanation:

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How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *

galben [10]

Answer:

52.5 mol O2

Explanation:

4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2

4 mol FeCl3 -> 6 mol O2

35.0 mol FeCl3 -> x

x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3

x=52.5 mol O2

5 0

3 years ago

Read 2 more answers

The most common element in the atmosphere are

Ivanshal [37]

Nitrogen and oxygen are the most prevalent in the atmosphere.

8 0

4 years ago

Find the mass in grams of 3.00 x 1023 molecules of F2

LUCKY_DIMON [66]

<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})$
Multiply: $\displaystyle 18.9306 \ g \ F_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0

3 years ago

Help please ASAP just with number 10

Dafna11 [192]

hhhhhhhgfffffffffffffffffffffffffffffndbd

8 0

3 years ago

The half-life of carbon-14 is 5730 years. therefore, 5730 years after being cut from a tree, a piece of wood will have 50.0% of

ddd [48]

For this problem, we use the formula for radioactive decay which is expressed as follows:<span>

An = Aoe^-kt

where An is the amount left after time t, Ao is the initial amount and k is a constant. </span>

<span>We can use the equation above to find the percent of the original substance at a given time. However, the time given here is equal to the half life of C-14. So the percent left would be 50% or half the original.

</span>

7 0

4 years ago