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sergiy2304 [10]
3 years ago
15

PLEASE HELP! - Will give brainliest to correct answer who explains how they got their answer! Thanks :)

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0
Sum of a geometric sequence for a1=first term and n=which one and r is common ratio is
S_n= \frac{a_1(1-r^n)}{1-r}
so
a1=1 students
r=4
n=5
S_n= \frac{1(1-4^5)}{1-4}
S_n= \frac{(1-1024)}{-3}
S_n= \frac{-1023}{-3}
314 people know


kirill [66]3 years ago
6 0
Just times by 4 on each of you answers 5 times and that will make it 4,096. I hope this is helpfull
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A construction worker fills a mold with concrete. This solid figure represents the mold.
nadezda [96]

Answer:

volume = 338 x 20 = 6760 cm^3

Step-by-step explanation:

large rectangular top area = 14 x 22 = 308 cm^2

small rectangular top area = 6x5 = 30 cm^2

total top area = 308 + 30 = 338 cm^2

volume = 338 x 20 = 6760 cm^3

4 0
3 years ago
What is the sum of the series? ∑ k=1 4 3 k 2
AleksAgata [21]

I got this on the calculator.

7 0
3 years ago
Read 2 more answers
What's the largest 3-digit base 14 integer?
Mars2501 [29]
Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}

Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number

Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}

Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}

Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}

The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer

Note: It is similar to how 999 is the largest 3-digit base 10 integer
3 0
3 years ago
The product of 1.3x10^-4 and a number n results in 2.6x10^12. What idle the value of n
Mademuasel [1]
1.3 x 10^-4 * n = <span>2.6 x 10^12
n = </span>2.6 x 10^12 / 1.3 x 10^-4
n = (2.6 / 1.3) x 10^16
n = 2 x 10^16

Answer
Idle the value of n = 2 x 10^16
5 0
3 years ago
Read 2 more answers
Geometry :))), please help me
amm1812

Answer:

x = -5

Step-by-step explanation:

Since these two triangles are similar, the ratio between the corresponding lengths of each triangle will be the same.

This means the ratio between one side of each triangle (e.g. AD and DC) will be the same as the ratio between a different side of each triangle (e.g. BE and BC).

So, to create an equation for the sides which contain the unknown 'x', we must first find the ratio between the two sides by using a different set of sides.

On the right side we are given 9 for AD, and 18 for DC.

9/18 = 0.5

This means that the extra length of the larger triangle from the smaller one (AD) is half the length of the smaller triangle (DC). We can use this to make an equation for x:

If AD/DC = 0.5, then BE/EC will also = 0.5

BE = x+23

EC = x+41

Therefore:

\frac{x+23}{x+41} = 0.5

Now we can solve by multiplying both sides by x+41 to eliminate the fraction:

x+23=0.5(x+41)

Now we multiply out the brackets and move the terms to different sides:

x+23=0.5x+20.5

0.5x = -2.5

x = -5

And if we substitute the -5 into the equations:

-5+23 = 18

-5 + 41 = 36

We will see that -5 does indeed give us the same ratio between the lengths:

18/36 = 0.5

Hope this helped!

4 0
3 years ago
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