I think a, im not a 100% sure tho!!!
Answer:
B. 1500 kg*m/s
Explanation:
Momentum p = m* v
In any type of collision, the total momentum is preserved!
The total momentum before and the total momentum after the collision is the same. We know the mass and speed after the collision so we can calculate the total momentum.
p1 + p2 =
m1*v1 + m2*v2
m1 = me = 300 kg
v1 = 3 m/s
v2 = 2 m/s
Substitute the given numbers:
300*3 + 300+2
900 + 600
1500 kg*m/s, which is answer B.
Answer:
transmission: the passing of a wave through an object
Explanation:
Answer:
17.6 N
Explanation:
The force exerted by the punter on the football is equal to the rate of change of momentum of the football:
where
is the change in momentum of the football
is the time elapsed
The change in momentum can be written as
where
m = 0.55 kg is the mass of the football
u = 0 is the initial velocity (the ball starts from rest)
v = 8.0 m/s is the final velocity
Combining the two equations and substituting the values, we find the force exerted on the ball:
The distance between two basket ball sized aluminium balls is 9714 m.
Explanation:
Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .
Coulomb's law formula => F = (k * Qb1 * Qb2)/r²
Given data :-
charge on ball 1 Qb1 = 6C
charge on ball 2 Qb2 = 14C
Force exerted F = 8000 N
k = 8.988 x 10^9 Nm²C−²(coulomb's constant).
substituting given values in the coulomb's formula
8000 = (( 8.988 x 10^9)*6*14)/r²
shifting r and 8000 to other sides
r² = (756 * 10^9)/8000
r = 9714 m.
Therefore the distance between two balls is r = 9714 m.
