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jok3333 [9.3K]
3 years ago
5

g typical coffee mug holds up to 12 oz (340 grams) of water. How much heat energy is required to warm enough water from 23⁰C to

95⁰C for a mug of hot tea?How many kWh would it take to heat this water with an electric stove?
Physics
1 answer:
Kryger [21]3 years ago
8 0

Answer:

Explanation:

Heat required to raise the temperature

= mass x specific heat x rise in temperature

= .34 x 4200 x ( 95 - 23 )

= 102816 J .

1 kWh = 1000 x 60 x 60 J

= 3600000 J

102816 J  = 102816 / 3600000

= .02856 kWh .

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These 2 processes cause watersheds to change.
Alex777 [14]
Tsunami and water bender those are 2 like avatars
5 0
3 years ago
Read 2 more answers
When a metal element bonds with a non mental element they are known as ____ bond
frozen [14]

Answer:

ionic

Explanation:

ionic bond is when a metal and nonmetal are bonded together

metallic bond is when a two metal are bonded

covalent is nonmetal and nonmetal bond or idk

4 0
3 years ago
At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s
andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. a = 1500\,\frac{km}{h^{2}}.

Explanation:

The average acceleration experimented by the car is:

\bar a = \frac{85\,\frac{km}{h} - 35\,\frac{km}{h} }{\frac{2}{60}\,h }

\bar a = 1500\,\frac{km}{h^{2}}

According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}

If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

a = 1500\,\frac{km}{h^{2}}

6 0
3 years ago
Unpolarized light passes through three polarizing filters. The first one is oriented with a horizontal transmission axis, the se
Xelga [282]

Answer:

10.028%

Explanation:

\theta = Angle between polarizer

The polarized light after passing through first polarizer

I=\frac{I_0}{2}

The polarized light after passing through second polarizer

I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow I_2=\frac{I_0}{2}cos^231.8\\\Rightarrow I_2=0.36115I_0

The polarized light after passing through third polarizer

I_3=I_2cos^2(90-31.8)\\\Rightarrow I_3=0.36115I_0cos^2(90-31.8)\\\Rightarrow I_3=0.10028I_0

\frac{I_3}{I_0}\times 100=\frac{0.10028I_0}{I_0}\times 100\\ =10.028\ \%

The percent of the light gets through this combination of filters is 10.028%

4 0
3 years ago
An ideal monatomic gas initially has a temperature of 300 K and a pressure of 5.79 atm. It is to expand from volume 420 cm3 to v
maxonik [38]

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

T = \frac{PV}{nR}

T_{i} = T_{f}

\frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR}

Where:

P_{i}: is the initial pressure = 5.79 atm

P_{f}: is the final pressure =?

V_{i}: is the initial volume = 420 cm³

V_{f}: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

3 0
3 years ago
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