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podryga [215]
2 years ago
14

When caring for wounds, doctors need to make sure wounds are not infected by bacteria. Which electromagnetic wave would doctors

most likely use for this purpose? gamma rays ultraviolet waves visible light X-rays.
Physics
2 answers:
Anna [14]2 years ago
6 0

Answer:

B. Ultraviolet waves

Explanation:

musickatia [10]2 years ago
5 0

Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm .Ultraviolet wave is used by doctors in order to keep the wounds away from bacteria.

<h3>What is ultravoilent wave ?</h3>

Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm. Ultravoilent wave is directly comes frim the sun. It is classified into the UV(A) , UV(B),UV(B).

Ultravoilet rays also effects the human eyes that s why sun glasses are used. The experiments here are compared and quantified to the effectiveness of the sunscreens with various strengths.

To learn more about the ultravoilent wave refr to the link;

brainly.com/question/19706211

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a baseball is hit straight up into the air. If the initial velocity was 20 m/s, how high will the ball go?How long will it be un
AleksAgata [21]
1) The motion of the ball is an uniformly accelerated motion, with constant acceleration equal to g=-10 m/s^2 (the negative sign means it is directed towards the ground).

For an uniformly accelerated motion, we can use the following relationship:
2gh=v_f^2-v_i^2
where h is the maximum height reached by the ball, v_i = 20 m/s is its initial velocity and v_f the velocity of the ball when it reaches the maximum height. But v_f=0 (when the ball reaches the maximum height, it stops before going down, so its velocity at that moment is zero), so we can use the relationship to  calculate h, the maximum height:
h=- \frac{v_i^2}{2g} =- \frac{20 m/s)^2}{2 \cdot (-10 m/s^2)} =20 m

2) We can find the time the ball takes to return to the ground by requiring that the space covered by the ball returns to zero: 
S(t)=0
where for an uniformly accelerated motion,
S(t)=v_i t +  \frac{1}{2} gt^2 =0
By solving this, we have two solutions: one is t=0, which corresponds to the moment the player hits the ball, the second one is
t=- \frac{2 v_i}{g}=- \frac{2 \cdot 20 m/s}{-10 m/s^2}=4 s
so, the ball returns to the ground after 4 s.

3) The velocity of the ball when it returns to the ground is given by:
v(t) = v_i +gt=20 m/s + (-10 m/s^2)(4 s)=-20 m/s
where the negative sign means the ball is going downwards.
8 0
3 years ago
A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s
Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
A 1.5 kg ball pushed with a force of 13.5 N accelerates to the left. What is the acceleration of the ball?​
GarryVolchara [31]

Explanation:

F= ma

13.5 =1.5a

1.5a/1.5 =13.5/1.5

a= 9 m/s^2

4 0
3 years ago
Suppose that instead of dropping the rock you throw it downwards so that its speed after falling 7 meters is 23.43 m/s. How much
Shkiper50 [21]

Answer:

3,298.1 Hz

Explanation:

Solution is attached

5 0
3 years ago
Read 2 more answers
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Fudgin [204]
I believe it’s financial aid
5 0
3 years ago
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