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4 years ago

Which formula stands for boric acid?

2 answers:

5 0

Which formula stands for boric acid?
H3BH3BO3HBrH3PO4

Answer: H3BO3

olasank [31]4 years ago

4 0

Boric acid is the name according to the traditional nomenclature. Boric acid is formed by the addition of three molecules of water to the boric oxide. The valence of boron is 3, and the valence of oxygen is 2, so boric oxide is B2O3. Now add three molecules of water: B2O3 + 3 H2O = H6 B2 O6 = H3 B O3. Then, the answer is that the formula that stands for boric acid is H3 BO3.

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Use the radius of a rubidium atom from the table below to calculate the number of rubidium atoms in a row 6.00 cm long. Assume t

levacccp [35]

Answer:

The answer to your question is: # of atoms = 2.42 x 10¹⁰

Explanation:

Data

radius = 248 pm

row = 6 cm long

Conversion

1 pm ------------------- 1 x 10 ⁻¹⁰ cm

248 pm -------------------- x

x = (248 x 1 x 10⁻¹⁰) / 1

x = 2.48 x 10⁻¹⁰ cm

Divide

# of atoms = 6 / 2.48 x 10⁻¹⁰

# of atoms = 2.42 x 10¹⁰

8 0

3 years ago

A buffer is prepared by mixing 204.0 mL of 0.452 mol/L hydrochloric acid (HCI) and 500.0 mL of 0.400 mol/L sodium acetate (NaCHC

Alex73 [517]

Answer:

pH of buffer is 4.81

Explanation:

The reaction between HCl and sodium acetate will product acetic acid. The presence of weak acid (acetic acid) and its salt will make a buffer.

The reaction will be:

$CH_{3}COONa + HCl --> CH_{3}COOH + NaCl$

Thus one mole each of HCl and acetate will give one mole of acetic acid.

The moles of HCl present = molarity X volume = 0.452 X 0.204 =0.092

moles of acetic acid formed on reaction of HCl with acetate = 0.092

Initial moles of sodium acetate present = molarity X volume = 0.4X0.5 =0.2

moles of sodium acetate left =0.108 mol

the pKa of acetic acid =4.74

The pH of buffer is calculated using Henderson Hassalbalch's equation :

pH = pKa + log $\frac{[salt]}{[acid]}$

$pH = 4.74 +log\frac{0.108}{0.092} =4.81$

8 0

4 years ago

Which of these characteristics differentiate electrons from protons and neutrons

mr Goodwill [35]

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4 years ago

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The answer is: [C]: Mg₂N₃.
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4 years ago