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vaieri [72.5K]
2 years ago
7

according to this passage when making healthcare decisions, how should a person approach the decision making process

Physics
1 answer:
Aleksandr-060686 [28]2 years ago
8 0

Answer:

What is your name?

Explanation:

no bro I don't know I am New of this app so I don't know

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A person is nearsighted with a far point of 75.0 cm. a. What focal length contact lens is needed to give him normal vision
BigorU [14]

Complete Question

The  complete question is  shown on the first uploaded image  

Answer:

a

  f=  -75 \ cm =  - 0.75 \ m

b

  P  =  -1.33 \ diopters

Explanation:

From the question we are told that

    The  image distance is  d_i =  -75 cm

The value of the image is negative because it is on the same side with the corrective glasses

    The  object distance is  d_o =  \infty

The  reason object distance  is because the object father than it being picture by the eye

General focal length is mathematically represented as

              \frac{1}{f}  =  \frac{1}{d_i}  -   \frac{1}{d_o}

substituting values

             \frac{1}{f}  =  \frac{1}{-75}  -   \frac{1}{\infty}

=>         f=  -75 \ cm =  - 0.75 \ m

Generally the power of the corrective lens is  mathematically represented as

        P  =  \frac{1}{f}

substituting values

       P  =  \frac{1}{-0.75}

        P  =  -1.33 \ diopters

7 0
3 years ago
A slingshot shoots a marble. It travels at an average speed of 15 m/s for 12 seconds before hitting it's target. How far does it
salantis [7]
Multiply m/s by 12 seconds to get meters by itself. 15(12)=180 m

6 0
3 years ago
An engineer can increase the magnitude of the magnification of a compound microscope by
jok3333 [9.3K]

Answer:

Option B

Explanation:

Magnification of Microscope is  

M = M_o \times M_e

Mo= Magnification of objective lens and

Me= magnification of the eyepiece.  

Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.  

Magnification,  

M\ \alpha\ \dfrac{1}{f}

when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.

Thus. Magnification will increase by decreasing the focal length.

The correct answer is Option B i.e. using shorter focal length

6 0
4 years ago
What is the force weight of a jaguar who jumps 3 meters to a tree branch with 2670 J of work?
fgiga [73]

Answer:

we \: know \: energy \:  =  \: force \:  \times distance \\ e = f \times d \\ so \: f \:  =  \frac{e}{d}  \\ so \: th \: force \: here \:  =  (\frac{2670}{3}) newton \\  = 890newton

Hope it helps

7 0
3 years ago
Pls help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
KatRina [158]

Answer:

Its answer d honey

Explanation:

Plzzzzzzz give 5 stars

4 0
3 years ago
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