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NARA [144]
3 years ago
5

Two people of equal mass attempt a tug-of-war with a 10 m long rope

Physics
2 answers:
ad-work [718]3 years ago
7 0

Answer:

Explanation:

As the poster has noted above in comment, the acceleration for each person will be the same. This is because when they tugon the rope, there will be tension force on the rope pulling the two persons towards each other. The tension force will be the same for them. As they also have equal mass, by Newton's Second Law of Motion, Force = mass * acceleration, their acceleration will be the same.

Lady_Fox [76]3 years ago
3 0

Answer:

When they pull on the rope, they each slide toward each other. How do their accelerations compare and how far does each person slide before they meet? The force on each will be the same so they will always have the same acceleration -- and, because of that, the same velocity and they will move the same distance.

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Having aced your Physics 2111 class, you get a sweet summer-job working in the International Space Station. Your room-mate, Cosm
Sphinxa [80]

Answer:

a

The speed is   s =  5.857 m/s

b

The distance is  D = 22.4  \  m

Explanation:

From the question we are told that

     The speed of the banana is  v =  16 \ m/s

   The distance from my  location is  d =  8.2  \ m  

     The time taken is  t = 1.4 \ s

The speed of the ice cream is

          s =  \frac{d}{t}

substituting values

        s =  \frac{8.4}{1.4}

        s =  5.857 m/s

The distance of separation between i and Valdimir is the same as the distance covered by the banana

   So  

          D =  v * t

substituting values

        D = 16 *  1.4

        D = 22.4  \  m

     

3 0
3 years ago
If given both the speed of light in a material and an incident angle. How can you find the refracted angle?
Basile [38]

Answer:

r = Sin^{-1}\left ( \frac{v Sini}{c} \right )

Explanation:

Let the speed of light in vacuum is c and the speed of light in medium is v. Let the angle of incidence is i.

By using the definition of refractive index

refractive index of the medium is given by

n = speed of light in vacuum / speed of light in medium

n = c / v  ..... (1)

Use Snell's law

n = Sin i / Sin r

Where, r be the angle of refraction

From equation (1)

c / v = Sin i / Sin r

Sin r = v Sin i / c

r = Sin^{-1}\left ( \frac{v Sini}{c} \right )

8 0
4 years ago
Write Newton's 3rd law. How would this law relate to a rocket ship taking off from the earth? Would this law affect the rocket s
irina1246 [14]

Answer:

Part A

Newton's 3rd law states that action and reaction are equal and opposite, mathematically, we have;

F_A = -F_B

Where;

F_A = The action force

F_B = The reaction force

Part B

The law indicates that the force with which a rocket ship uses in taking off from the Earth, F_A is equal in magnitude, and opposite in direction to the reaction force of the Earth to the motion of the rocket, (-)F_B

Part C

The law is a universal law, and it will also affect the rocket ship in space, as the force of the jet from the exhaust is directed towards Earth while in space, the rocket is propelled deeper into space

Explanation:

6 0
3 years ago
Heat is best defined as
allochka39001 [22]
C. A flow of matter from one point to another. 
7 0
4 years ago
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At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 25 cm on a spring with a spring con
KiRa [710]

Answer:

0.11m/s

Explanation:

To solve the exercise it is necessary to apply the concepts related to the conservation of both: kinetic and spring energy(Elastic potential energy), in this way

Kinetic Energy = Elastic potential energy

KE = SE

\frac{1}{2}mv^2 = \frac{1}{2}kX^2

Where,

m=mass

v=velocity

k=spring constant

x=amount of compression

Re-arrange the equation to find the velocity we have,

v^2 = \frac{kX^2}{m}

v^2 = \frac{10(0.25)^2}{50}

v = \sqrt{0.0125}

v = 0.11m/s

Therefore the maximum speed of the bananas is 0.11m/s

8 0
3 years ago
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