Answer:
Part A
Newton's 3rd law states that action and reaction are equal and opposite, mathematically, we have;
= -
Where;
= The action force
= The reaction force
Part B
The law indicates that the force with which a rocket ship uses in taking off from the Earth, is equal in magnitude, and opposite in direction to the reaction force of the Earth to the motion of the rocket, (-)
Part C
The law is a universal law, and it will also affect the rocket ship in space, as the force of the jet from the exhaust is directed towards Earth while in space, the rocket is propelled deeper into space
Explanation:
Answer:
When x = 2.8 cm,
When x = 5.5 cm,
when x = 7.3 cm,
When x = 11.0 cm,
Explanation:
According to Biot-Savart law,
.......................(1)
R = 11.0 cm = 0.11 m
I = 17.0 A
N = 300 turns
When x₁ = 2.8 cm = 0.028 m
When x₂ = 5.5cm = 0.055 m
When x₃ = 7.3 cm = 0.073 m
When X₄ = 11.0 cm = 0.11 m
Answer:
vavg = 53.7 km/h
Explanation:
In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:
where xf - xo = total displacement = 1250 Km
If we choose t₀ = 0, ⇒ t = 23h 16'= 23h + 0.27 h = 23.27 h
⇒
Answer:
T =176 N
Explanation:
from diagram
F -(m_1+m_2_g) = (m_1+m_2_g)a
440 - (6+4)g = (6+4)a
a =\frac{440-10*9.8}{10}
a =34.2 m/s^2
frrom free body diagram of mass m2 = 4kg
T -m_2g =m_2a
T = m_2(g +a)
T = 4(9.81+34.2)
T =176 N
