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3 years ago

Heat transfer from the Sun to the Moon is mostly through the process of *

Physics

2 answers:

boyakko [2]3 years ago

7 0

radiation since the suns rays are ultraviolet which is a form of radiation

inysia [295]3 years ago

7 0

Heat transfer from the Sun to the Moon is mostly through the process of Radiation.

<u>Explanation: </u>

In space, the heat is being transferred through the process of radiation. There is no atmosphere in the moon so it will get heat or cool by the process of conduction or convection.

In space, heat gets transferred by radiation which mainly takes place in the infrared band of electromagnetic waves. Radiation can transmit heat by the electromagnetic wave. It can take the heat transfer process in the vacuum.

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A rope is wrapped around a pulley many times. The pulley can be modeled as a solid disk of radius R and mass M, and a mass mA ha

aleksandr82 [10.1K]

The magnitude of the tangential acceleration of the hanging mass is 2mg/MR

<h3>Tangential acceleration of the hanging mass</h3>

The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;

τ = Iα

Where;

I is the moment of inertia
α is the angular velocity

$\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}$

Where;

m is the hanging mass
M is the mass of solid disk

The tangential acceleration is calculated as follows;

$a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}$

Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR

Learn more about tangential acceleration here: brainly.com/question/11476496

4 0

3 years ago

Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also incr

Annette [7]

Answer:

P = 251,916.667 W

Cost = 2,267.25 cents

Explanation:

To solve this question we will use the Work Energy Theorem, which is

$W = dP + dK\\$

Where

$dP$ = Change in Potential Energy

$dK$ = Change in Kinetic Energy

Change in Potential Energy

$P_{i} = mgh_{i}\\ P_{f} = mgh_{f}$

Where

$P_{i}$ = Initial Potential Energy

$P_{f}$ = Final Potential Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$h_{i}$ = Initial Height = 0

$h_{f}$ = Final Height = 30 m

Inputting the values we get the answer for $dP$

$dP = P_{f} - P_{i}\\dP= mgh_{f} - mgh_{i}\\ dP= 10000(9.81)(30) - 0\\ dP= 2943000$

Change in Kinetic Energy

$K_{i} = \frac{1}{2} mv_{i} ^2\\ K_{f} = \frac{1}{2} mv_{f} ^2$

Where

$K_{i}$ = Initial Kinetic Energy

$K_{f}$ = Final Kinetic Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$v_{i}$ = Initial Velocity = 0 m/2

$v_{f}$ = Final Velocity = 4 m/s

Inputting the values we get the answer for $dK$

$dK = K_{f} - K_{i}\\ dK = \frac{1}{2} mv_{f} ^2 - \frac{1}{2} mv_{i} ^2\\ dK = \frac{1}{2} (10000)(4)^2 - 0 \\ dK = 80000$

Total Work

$W = dP + dK\\$

Inputting the values

$W = 2943000 + 80000$

$W = 3,023,000$

a) Finding the useful Power Output

$P = \frac{W}{t}$

Where

$P$ = Power Output

$W$ = Work Done = 3,023,000J

$t$ = Time = 12s

Inputting the values

$P = \frac{3,023,000}{12}\\ P = 251,916.667$

P = 251,916.667 W

b) Finding the Total Cost

Cost = $0.0900 x P/1000

Cost = $0.0900 x (251,916.667/1000)

Cost = $22.67 or 2,267.25 cents

4 0

4 years ago

URGENT!!!!! If a 6 Ω resistor is in a circuit connected to a voltage source, and the current through the circuit is 2 amps, what

Eduardwww [97]

Answer:

Explanation:

according to ohms law we know that

v=IR

given current =2 amps

given resistance =6Ω

so voltage is

v=2*6 =12 V

3 0

4 years ago

Describe how the eye changes visible light to an image

mr_godi [17]

First, light passes through the cornea. It bends the light inward. The light then passes through the pupil. After entering the eye through the pupil, the light passes through the lens. It focuses the light to create an image on the retina. It consists of light receptor cells called rods and cones. The rods and cones send nerve impulses about the image to the brain through the optic nerve. The visual cortex of the brain receives and interprets the information and tells you what you are seeing

3 0

4 years ago

A tuning fork produced four beats per second with a second, 270-Hz tuning fork. What are the two possible frequencies of the fir

EleoNora [17]

Answer:

frequency of the first tuning fork can be 274 Hz or 266 Hz

Explanation:

Given data :

we have number of beats per second = 4

thus, it can also be written as

Beat frequency of the tuning fork, v = 4 Hz

Frequency of the tuning fork, f = 270 Hz

now, the beat frequency is actually the difference of the consecutive frequency.

thus, we have

Frequency of the first tuning fork as = 270 Hz + 4 Hz = 274 Hz

Frequency of the first tuning fork as = 270 Hz - 4 Hz = 266 Hz

Therefore, the frequency of the first tuning fork can be 274 Hz or 266 Hz

7 0

3 years ago