Question

PLS ANSWER ME QUICK!!

Answer 1

Answer:

45g

Explanation:

first we will find out which is the limiting reactant (hope you know how to find it)

Cao is the limiting reactant

so

we will find the number of moles of cao which is 0.45 mol

as according to the equation cao and caco3 have ratios 1:1 so both will have the same no. of moles

then by multiplying 0.45mol by 100 (mr of caco3) we will get the mass of caco3 which is 45g

Answer 2

Answer:

100.09 amu is the answer.