Answer:
Solar eclipse
Explanation:
A solar eclipse is when the moon passes between the sun and Earth, causing it to go dark and to give the moon a halo effect :D hope this helped!
Explanation:
It is known that wave intensity is the power to area ratio.
Mathematically, I = ![\frac{P}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BA%7D)
As it is given that power is 28.0 W and area is
.
Therefore, sound intensity will be calculated as follows.
I = ![\frac{P}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BA%7D)
= ![\frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B28.0%20W%7D%7B4%20%5Ctimes%203.14%20%5Ctimes%207%20%5Ctimes%2010%5E%7B-5%7D%20m%5E%7B2%7D%7D)
= ![0.318 \times 10^{5} W/m^{2}](https://tex.z-dn.net/?f=0.318%20%5Ctimes%2010%5E%7B5%7D%20W%2Fm%5E%7B2%7D)
or, = ![3.18 \times 10^{4} W/m^{2}](https://tex.z-dn.net/?f=3.18%20%5Ctimes%2010%5E%7B4%7D%20W%2Fm%5E%7B2%7D)
Thus, we can conclude that sound intensity at the position of the microphone is
.
Answer:
a = 2.72 [m/s2]
Explanation:
To solve this problem we must use the following kinematics equation:
![v_{f} =v_{o} + a*t](https://tex.z-dn.net/?f=v_%7Bf%7D%20%3Dv_%7Bo%7D%20%2B%20a%2At)
where:
Vf = final velocity = 1200 [km/h]
Vo = initial velocity = 25 [km/h]
t = time = 2 [min] = 2/60 = 0.0333 [h]
1200 = 25 + (a*0.0333)
a = 35250.35 [km/h2]
if we convert these units to units of meters per second squared
![35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]](https://tex.z-dn.net/?f=35250.35%5B%5Cfrac%7Bkm%7D%7Bh%5E%7B2%7D%20%7D%5D%2A%28%5Cfrac%7B1%7D%7B3600%5E%7B2%7D%20%7D%29%2A%5B%5Cfrac%7Bh%5E%7B2%7D%20%7D%7Bs%5E%7B2%7D%20%7D%20%5D%2A%28%5Cfrac%7B1000%7D%7B1%7D%20%29%2A%5B%5Cfrac%7Bm%7D%7Bkm%7D%20%5D%20%3D%202.72%20%5B%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%5D)
Answer:
The pressure of the remaining gas in the tank is 6.4 atm.
Explanation:
Given that,
Temperature T = 13+273=286 K
Pressure = 10.0 atm
We need to calculate the pressure of the remaining gas
Using equation of ideal gas
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
For a gas
![P_{1}V_{1}=nRT_{1}](https://tex.z-dn.net/?f=P_%7B1%7DV_%7B1%7D%3DnRT_%7B1%7D)
Where, P = pressure
V = volume
T = temperature
Put the value in the equation
....(I)
When the temperature of the gas is increased
Then,
....(II)
Divided equation (I) by equation (II)
![\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_%7B1%7DV%7D%7BP_%7B2%7DV%7D%3D%5Cdfrac%7BnRT_%7B1%7D%7D%7B%5Cdfrac%7Bn%7D%7B2%7DRT_%7B2%7D%7D)
![\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}](https://tex.z-dn.net/?f=%5Cdfrac%7B10%5Ctimes%20V%7D%7BP_%7B2%7DV%7D%3D%5Cdfrac%7BnR%5Ctimes286%7D%7B%5Cdfrac%7Bn%7D%7B2%7DR368%7D)
![P_{2}=\dfrac{10\times368}{2\times286}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cdfrac%7B10%5Ctimes368%7D%7B2%5Ctimes286%7D)
![P_{2}= 6.433\ atm](https://tex.z-dn.net/?f=P_%7B2%7D%3D%206.433%5C%20atm)
![P_{2}=6.4\ atm](https://tex.z-dn.net/?f=P_%7B2%7D%3D6.4%5C%20atm)
Hence, The pressure of the remaining gas in the tank is 6.4 atm.