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Alenkinab [10]
3 years ago
9

Which of the following is an example of projectile

Physics
1 answer:
jonny [76]3 years ago
7 0

Answer:

The answer is choice A.

Explanation:

Assuming you are in a situation with a gravitational field. You can divide the motion of the bullet into two components. One horizontal and the other in the vertical.

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A copper wire has a radius of 3.5 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
denpristay [2]

Answer:

The tensile stress on the wire is 550 MPa.

Explanation:

Given;

Radius of copper wire, R = 3.5 mm

extension of the copper wire, e =  5.0×10⁻³ L

L is the original length of the copper wire,

Young's modulus for copper, Y =  11×10¹⁰Pa.

Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Y =\frac{Tensile \ stress}{Tensile \ strain} \\\\Tensile \ stress = Y*Tensile \ strain\\\\But, Tensile \ strain = \frac{extension}{original \ Length} = \frac{5.0*10^{-3} L}{L} = 5.0*10^{-3}\\\\Tensile \ stress = 11*10^{10} *5.0*10^{-3} \ = 550*10^6 \ Pa

Therefore, the tensile stress on the wire is 550 MPa.

8 0
3 years ago
Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the
Alenkasestr [34]

Answer:

The acceleration of car 2 is four times of the acceleration of car 1.

Explanation:

The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :

a=\dfrac{v^2}{r}

In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.

So,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}

1 and 2 represent car 1 and car 2 respectively.

v_2=2v_1

So,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1

So, the acceleration of car 2 is four times of the acceleration of car 1.

4 0
3 years ago
A car traveling at 12 m/s slows down with an acceleration of -1.5 m/s2. What is the
Alex777 [14]

Answer:

using s=ut +0.5at^2

u=12m/s

a=-1.5m/s2

t=6 s

s=54m

7 0
3 years ago
Match the words in the left-hand column to the appropriate blanks in the sentences in the right-hand column. Use each word only
Likurg_2 [28]

Answer:

1. Solar nebula

2. Planetesimals.

3. Heavy bombardment.

4. Accretion.

5. Solar winds

6. Condensation.

7. Frost line.

8. Radiometric dating.

Explanation:

  • Solar nebula is a cloud of gases and was created by the gravitational collapse of the dust and hydrogen in a form molecular cloud and has a hot dense center.
  • Planetesimals are solid objects that are formed by the debris from the disks and believed to have formed some 46 billion years.
  • The period of heavy bombardment is known to have been due to the intense spike of asteroids about 4 billion years ago. That lead to the formation of craters on earth and moon.
  • Accretion is the process by which the growth increase and is the accumulation of layers of matter over the surface.
  • Solar winds are those blows from the surface of the sun and consist of charged particles.
  • Condensation is a change in the physical state of gas into the liquid phase.
  • Frost line is the depth of the water is expected to freeze and can cool enough to form hydrogen compounds to solid ice grains.
  • The radiometric dating technique is allows us to determine the absolute age of rocks and carbon contents.
5 0
3 years ago
A pilot flies her route in two straight-line segments. The displacement vector A for the first segment has a magnitude of 243 km
velikii [3]

Answer:

a) R=126Km

b) \theta=74.6\textdegree

Explanation:

From the question we are told that:

1st segment

243km at Angle=30

2nd segment

178km West

Resolving to the X axis

F_x=243cos30+178

F_x=33.44Km

Resolving to the Y axis

F_y=243sin30+178sin0

R=\sqrt{F_y^2+F_x^2}

F_y=121.5Km

Therefore

Generally the equation for Directional Angle is mathematically given by

\theta=tan^{-1}\frac{F_y}{F_x}

\theta=tan^{-1}\frac{121.5}{33.44}

\theta=74.6\textdegree

Generally the equation for Magnitude is mathematically given by

R=\sqrt{F_y^2+F_x^2}

R=\sqrt{33.44^2+121.5^2}

R=126Km

8 0
3 years ago
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