All categories

3 years ago

A sample of nitrogen occupies 10.0 liters at 25oC , what would be the new volume at 20oC?

Chemistry

2 answers:

Julli [10]3 years ago

5 0

Answer:

8.0 L

Explanation:

Boyle's Law

V₁T₂ = V₂T₁
V₂ = V₁T₂ / T₁

Given :

V₁ = 10.0 L
T₁ = 25°C
T₂ = 20°C

Solving :

V₂ = 10 x 20 / 25
V₂ = 200 / 25
V₂ = 8.0 L

katrin [286]3 years ago

4 0

V1=10L
T1=25°C
T2=20°C

Apply Charles law

$\\ \bf\bull\rightarrowtail V1T2=V_2T1$

$\\ \bf\bull\rightarrowtail 10(20)=25V_2$

$\\ \bf\bull\rightarrowtail 200=25V_2$

$\\ \bf\bull\rightarrowtail V_2=8L$

You might be interested in

5. What happens to the mass when you change the volume? It decreases

anastassius [24]

Explanation:If the mass of the object stays the same but the volume of the object decreases then its density becomes greater. If the volume of the object stays the same but the mass of the object increases then its density becomes greater.

7 0

3 years ago

Why is it important for us to study outer space?

AleksAgata [21]

Answer:

So you know the things about outer space like facts that you might not know

8 0

3 years ago

If 45.0 mL of ethanol (density=0.789 g/mL) initially at 9.0 C is mixed with 45.0 mL of water (density=1.0 g/mL) initially at 28.

Klio2033 [76]

Answer : The final temperature of the mixture is $22.7^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

$(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.3J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol

$m_2$ = mass of water

$\rho_1$ = density of ethanol = 0.789 g/mL

$\rho_2$ = density of water = 1.0 g/mL

$V_1$ = volume of ethanol = 45.0 mL

$V_2$ = volume of water = 45.0 mL

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $9.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get

$(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.7^oC$

Therefore, the final temperature of the mixture is $22.7^oC$

4 0

3 years ago

They all have the same choices but one of them its not gonna be used.

Dima020 [189]

Answer:

limiting reactant

Explanation:

it is consumed totally

3 0

3 years ago

A solid has a high to very high melting point, great hardness , and poor electrical conduction, this is an_______solid. a. ionic

Elena L [17]

The correct answer is D. A solid has a high to very high melting point, great hardness , and poor electrical conduction, this is a covalent network solid. This is because of the large amount of energy required to break these bonds, the said properties are exhibited by these solids.

6 0

3 years ago