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Murljashka [212]

2 years ago

7

PLEASE HELP!!!!

2 answers:

Vladimir79 [104]2 years ago

5 0

Answer: 9.33

Step-by-step explanation: you divide Saturn by earth

Maurinko [17]2 years ago

3 0

Answer:

8.33

Step-by-step explanation:

Answer: 8.33 minutes will it take to travel from the sun to the earth. Step-by-step explanation: Distance of the Earth from the Sun = d = 1 km = 1000 m.

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Sean read 15 of a book in 112 hours.

makvit [3.9K]

Sean read 15 of a book in = 112 hours,
so, 1 of a book in = 112/15

Now, 12 of a book would be: 112/15 * 12 = 112/5 * 4 = 89.6

89.6 = 89 6/10 = 89 3/5

In short, Your Answer would be 89 3/5 hours

Hope this helps!

8 0

4 years ago

Can someone please help me I really need help please <br> I don’t understand this

anastassius [24]

Step-by-step explanation:

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7 0

3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

What are line plots with fractions

GREYUIT [131]

Line plots are like for rounding them or put them in order fracton

3 0

3 years ago

QveST [7]

The answer should be:

Domain: All real

numbers

greater than or

equal to 0 and

less than or

equal to 100

Range: all real

numbers

greater than or

equal to 0 and

less than or

equal to 50

3 0

3 years ago