Answer:
they would react to make aluminum oxide and nitrogen
Explanation:
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The given reaction is as follows:
2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ
It is known that dSsurr = -dHsys / T (Temp = 355 K)
So, dSsurr = - (-114 × 1000) / 355
dSsurr = +321.12 J/K
Hence, the value of dSsurr is +321.12 J/K
For a reaction to be spontaneous, dG<0,
Also dStotal = dSsys + dSsurr > 0
It is known that dG = dHsys - TdSsys,
Now let us assume,
dG<0
Also, dStotal = dSsys + dSsurr > 0
(-114 × 1000) - (355 × dSsys) <0
355 × dSsys > -114 × 1000
dSsys > -321
dSsys >dSsurr
dSsys + dSsurr > 0
dStotal > 0
Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.
The oxidation number sulfur in H₂S is -2.
A compound's total number of oxidations must be zero.
The two hydrogen atoms in the chemical hydrogen sulfide, H₂S, each have an oxidation number of +1, making a total of +2. As a result, the compound's sulfur has an oxidation number of -2, and the total number of oxidations is 0.
Assume that the sulfur atom in H₂S has an oxidation number of x.
S be x.
Now,
2+x=0
⇒x=−2
<h3>What is oxidation number?</h3>
The total number of electrons that an atom either receives or loses in order to create a chemical connection with another atom is known as the oxidation number, also known as the oxidation state.
Depending on whether we are taking into account the electronegativity of the atoms or not, these phrases can occasionally have a distinct meaning. Coordination chemistry commonly makes use of the phrase "oxidation number."
<h3>What distinguishes an oxidation number from an oxidation state?</h3>
In contrast to the oxidation state, which indicates how oxidised an atom is in a molecule, the oxidation number describes the charge that the core metal atom will retain once all ligands have been removed.
To know more about oxidation number:
brainly.com/question/13182308
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Answer:
Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Explanation:
The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.
-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.
This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
