1) Convert 12.9 liters of Oxygen to mol at the given conditions:
PV = nRT ⇒ n = PV/RT
n = [1.2atm*12.9 l] / [0.082 atm l /K mol * 297K]
n = 0.636 mol of O2
2) use the stoichiometry derived from the balanced chemical equation
1mol C2H4 / 3 mol O2 = x mol C2H4 / 0.636 mol O2
x = 0.636 / 3 mol O2 = 0.212 mol O2.
Answer: 0.212 mol O2
Nitrous acid, hno2, has an acid dissociation constant - ka of 7. 1 ✕ 10-4. what are [h3o ], [no2-], and [oh -] in 0. 40 m hno2 - 4829 M [OH^-] = 1.439 x 10^-14 M
The acid dissociation constant (Ka) is used to differentiate between strong and weak acids. Strong acids have very high Ka values. The Ka value is determined by examining the equilibrium constant for acid dissociation. The acid dissociates more readily as the Ka increases.
The original molecular definition of an acid, according to Arrhenius, is a molecule that dissociates in an aqueous solution, releasing the hydrogen ion H+ (a proton): HA A + H+. acid dissociation constant is an equilibrium constant for this dissociation reaction.
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The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.
Answer:
A
Explanation:
its a because that is the first thing you do
Answer:
Decomposition Reaction
Explanation:
If you are referring to what type of reaction that occurred then the answer would be decomposition reaction.
This is a chemical reaction where one reactant is broken down into two or more products.
REACTANT → PRODUCT
AB → A + B
The products can be two or more elements or two or more compounds, depending on what was decomposed.
