All categories

2 years ago

What is responsible for the sharp decrease in ionization energy between the elements with 2 and 3 atomic number? 10 and 11?

1 answer:

6 0

An extra shell, which means further distance between those electrons in the valence shell and the nucleus. Ionisation energy refers to the energy required to remove valence electrons. There will be more energy required if the valence electrons are closer to the nucleus that have a positive charge, because of more attraction. If there is an extra shell, there is further distance, less attraction and hence less energy required.

You might be interested in

A sample of methane occupies a volume of 370.0 ml at 25 oC and exerts a pressure of 1020 mm Hg. If the volume is allowed to expa

vagabundo [1.1K]

Answer:

744.9 mmHg ≅ 745 mmHg

Explanation:

The base to solve this, is the Ideal Gases Law. The mentioned formula is:

P . V = n . R . T

To compare two situations, we can propose:

For the first situation P₁ . V₁ = n₁. R . T₁

For the second situation P₂ . V₂ = n₂ . R . T₂

As the sample has the same moles and R is a constant value, we can avoid them so: (P₁ . V₁) / T₁ = (P₂ . V₂) / T₂

We need to make Tº unit conversion:

25ºC + 273 = 298K

We replace data → (370 mL . 1020 mmHg) / 298K = (P . 510 mL) / 300 K

(377400 mL.mmHg / 298K) . 300 K = P . 510 mL

379932.8 mL . mmHg = P . 510 mL

(379932.8 mL . mmHg) / 510 mL = P → 744.9 mmHg

7 0

3 years ago

How many liters of 1.2M solution can be prepared with 0.50 moles of C6H12O6

BigorU [14]

First you need to know the molecular weight of sugar (C6H12O6) which is 180.156g/mol
You have half a mole so you have 90.078g
If you wanted to make 1L of a 1.2M solution of glucose you would need 180.156*1.2=216.1872g
But you only have 90.078g
So you need to figure out how much this 90.078g will make if the solution must be 1.2M:
90.078g/216.1872g=xL/1L
solve for the X and you get 0.416666666...
so 416.7ml or 0.417L

5 0

3 years ago

Help--? im so bad at science ugh

sukhopar [10]

Answer:

a volcano is convergent

Explanation:

8 0

3 years ago

Read 2 more answers

Chlorine (Cl) is 76% chlorine-35 and 24% chlorine-37. Determine the average atomic mass of chlorine. Show/Explain work.

Flura [38]

Answer:

Average atomic mass of chlorine is 35.48 amu.

Explanation:

Given data:

Percent abundance of Cl-35 = 76%

Percent abundance of Cl-37 = 24%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100

Average atomic mass = (76×35)+(24×37) /100

Average atomic mass = 2660 + 888 / 100

Average atomic mass = 3548/ 100

Average atomic mass = 35.48 amu

Average atomic mass of chlorine is 35.48 amu.

4 0

3 years ago

There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride, molecular formula ) at thre

RideAnS [48]

Answer:

The correct answer is - option C.

Explanation:

Given: the melting point of HCl is

-114.8 °C, which suggests that below this temperature HCl will be solid.

and, since the boiling point of HCl is - 85.1 °C. It is also suggested that above this temperature HCl will be gas, Therefore.

Solid -114.8 - Ordered arrangement

Liquid -85.1c - Less orderly arranged

Gaseous - Least orderly arranged

Thus, at —90 °C, HCl will be present 'in the liquid state, At — 1 °C, HCl will be present in the gaseous state and at -129 °C, HCl will be present in the solid-state. So, the molecules will be organized in a more orderly manner .

Thus, the correct answer is - option C

8 0

3 years ago