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pantera1 [17]
3 years ago
5

If each of the following compounds/ions were placed between 2 electrically charged plates (one positive and one negative) Which

would have a net attraction to the positive charged end, which would have a net attraction to the negative charge, which would be attracted to both and how is this possible? CH4, CH2Cl2, H3O+, H20, C2H2Cl2(including all 3 isomers), CO2, CO32-, and O3.
Chemistry
1 answer:
GREYUIT [131]3 years ago
4 0
<span>If a molecule wants to interact with an electric field. it should have a permanent dipole momentum. so first check the polarity. for example CH4 is not polar. CH2Cl2 is polar (so yes), H3O)+ is obvious that is polar. H2O yes. C2H2Cl2 in trans form is not polar but in cis form yes. CO2 is non-polar. Ozone is polar. </span>
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um pretty sure this is it

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What does it mean to optimize a solution ?<br> How are solutions optimize
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6 0
3 years ago
One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su
solong [7]

Answer:

89.55~\%~of~Fe_2O_3~in~the~sample

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The first step in this reaction is the<u> converstion from Kg</u> of Fe <u>to</u>  <u>grams</u> of Fe_2O_3.

1.19x10^3~Kg~Fe~\frac{1000g~Fe}{1~Kg~Fe}~\frac{1~mol~Fe}{55.84~g~Fe}~\frac{1~mol~Fe_2O_3}{2~mol~Fe}~\frac{159.68~g~Fe_2O_3}{1~mol~Fe_2O_3}~\frac{1~Kg~Fe_2O_3}{1000~g~Fe_2O_3}

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Then we can calculate the <u>percentage</u> of  Fe_2O_3 in the sample:

\%~Fe_2O_3~=~\frac{1.7x10^3~Kg~Fe_2O_3}{1.9x10^3~Kg~Sample}*100

89.55~\%~of~Fe_2O_3~in~the~sample

3 0
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