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pantera1 [17]
3 years ago
5

If each of the following compounds/ions were placed between 2 electrically charged plates (one positive and one negative) Which

would have a net attraction to the positive charged end, which would have a net attraction to the negative charge, which would be attracted to both and how is this possible? CH4, CH2Cl2, H3O+, H20, C2H2Cl2(including all 3 isomers), CO2, CO32-, and O3.
Chemistry
1 answer:
GREYUIT [131]3 years ago
4 0
<span>If a molecule wants to interact with an electric field. it should have a permanent dipole momentum. so first check the polarity. for example CH4 is not polar. CH2Cl2 is polar (so yes), H3O)+ is obvious that is polar. H2O yes. C2H2Cl2 in trans form is not polar but in cis form yes. CO2 is non-polar. Ozone is polar. </span>
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What ion will be formed by the selenium atom shown below when it has a stable set of valence electrons?
Bas_tet [7]

Answer:

Explanation:

D. Se2−

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3 years ago
When 20.00 mL of an unknown monoprotic acid is titrated with 0.125 M NaOH, it takes 15.00 mL to reach the endpoint. What is the
ohaa [14]

Answer:

About 0.0940 M.

Explanation:

Recall that NaOH is a strong base, so it dissociates completely into Na⁺ and OH⁻ ions. Because the acid is monoprotic, we can represent it with HA. Thus, the reaction between HA and NaOH is:


\displaystyle \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)} \longrightarrow \text{H$_2$O}_\text{($\ell$)} + \text{A}^-_\text{(aq)}

Using the fact that it took 15.00 mL of NaOH to reach the endpoint, determine the number of HA that was reacted with:

\displaystyle \begin{aligned} 15.00\text{ mL} &\cdot \frac{0.125\text{ mol NaOH}}{1\text{ L}} \cdot \frac{1\text{ L}}{1000\text{ mL}} \\ \\  &\cdot \frac{1\text{ mol OH}^-}{1\text{ mol NaOH}} \cdot \frac{1\text{ mol HA}}{1\text{ mol OH}^-}\\ \\  & = 0.00188\text{ mol HA}\end{aligned}

Therefore, the molarity of the original solution was:


\displaystyle \left[ \text{HA}\right] = \frac{0.00188\text{ mol}}{20.00\text{ mL}} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 0.0940\text{ M}

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3 0
2 years ago
Need helpppppp hurry pls, i just really need help
mojhsa [17]

Answer:

6.8 mole of O₂

Explanation:

Given expression:

       2H₂   +   O₂   →   2H₂O

Number of moles of H₂ = 13.6moles

Unknown:

Number of moles of O₂  = ?

Solution:

In the given problem, we are to find the number of moles of oxygen gas that will use up 13.6mole of hydrogen gas;

 From the reaction equation;

             2 mole of H₂ will completely react with 1 mole of O₂

         13.6 moles of H₂ will completely be used up by \frac{13.6}{2} mole of  O₂

                                                                                        = 6.8 mole of O₂

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