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4 years ago

HBr + Mg(OH)2 ---> MgBr2 + H2O

1 answer:

swat324 years ago

4 0

Hello Camkirkland,
I think that you are trying to balance this equation.
In order to balance a chemical equation, the numbers of atoms of each element must be equal on both sides of the equation.

In this particular equation, the answer would be (2) HBr + (1) Mg(OH)2 ---> (1) MgBr2 + (2) H2O.

Hope this answers your question!

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Molarity, chemistry general chemistry

Anna007 [38]

Answer:

a. 0.026 M

Explanation:

Molarity is a measure of the molar concentration of a solution. It can be calculated by using the following formula:

Molarity = n/V

Where;

n = number of moles (mol)

V = Volume of solution (L)

Based on the information provided;

V = 23.2mL = 23.2/1000 = 0.0232 L

n = ?

To get the number of moles of KHP, we use the formula:

mole = mass/molar mass

mole (n) = 0.123/204.2

mole (n) = 0.0006024mol

Molarity = n/V

Molarity = 0.0006024 ÷ 0.0232

Molarity = 6.024 × 10^-4 ÷ 2.32 × 10^-2

Molarity = 6.024/2.32 × 10^(-4--2)

Molarity = 2.59 × 10^-2

Molarity = 0.026 M

4 0

3 years ago

What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 3

grandymaker [24]

Mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current is 19.55 g

Given, I=8.70A, t=33.5min=33.5*60=2010 sec, m of Ag = 19600g M=107.87 g/mol

From faradays law we can write q=I*t= 8.70*2010=17487 C.

moles of Ag =17487/ 19600=0.1812 moles

Ag deposited = 0.1812*107.87 = 19.55 g

<h3>Silver </h3>

Having the atomic number 47 and the Latin word argentum, which means "bright" or "white," silver is a chemical element. Its symbol is Ag. The highest electrical, thermal, and reflectivity of any metal are displayed by this transition metal, which is soft, white, and lustrous. The metal can be found in the Earth's crust in three different forms: as an alloy with other metals like gold and in minerals like argentite and chlorargyrite. It can also be found in its pure, free elemental form, also known as "native silver." During the refining of copper, gold, lead, and zinc, the majority of silver is created as a byproduct. As a valuable metal, silver has long been treasured.

What mass of silver can be plated onto an object in 33. 5 minutes at 8. 70 a of current? ag (aq) e- → ag(s) 19. 6 g 9. 78 g 0. 326 g 3. 07 g 0. 102 g

Learn more about Silver here:

brainly.com/question/14587716

#SPJ4

4 0

2 years ago

Examples of type of matter that_ through the environment are carbon, nitrogen, and water

oee [108]

Answer:

examples of type of matter that circulate through the environment are carbon, nitrogen, and water

8 0

3 years ago

What is the percent yield for the reaction below when

kumpel [21]

Answer:

Percent yield of reaction is 150%.

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂ → 2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

SO₂ : SO₃

2 : 2

9.1 : 9.1

O₂ : SO₃

1 : 2

2.5 : 2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

8 0

3 years ago

The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the molar solubility of this compound.

mafiozo [28]

As,
CuCO₃   ⇆ Cu²⁺ + CO₃²⁻
So,
Kc = [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
Kc (CuCO₃) = [Cu²⁺] [CO₃²⁻]
Or,
Ksp = [Cu²⁺] [CO₃²⁻]
As,
Ksp = 1.4 × 10⁻¹⁰
So,
1.4 × 10⁻¹⁰ = [x] [x]
Or,
x² =  1.4 × 10⁻¹⁰
Or,
x = 1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
x =  1.18 × 10⁻⁵ mol/L × 123.526 g/mol

x = 1.45 × 10⁻³ g/L

3 0

3 years ago

____ HBr + ____ Mg(OH)2 ---> ____ MgBr2 + ____ H2O

HBr + Mg(OH)2 ---> MgBr2 + H2O