Given:
Be - Beryllium - 9,3227
C - Carbon - 11,2603
O - Oxygen - 13,6181
Ne - Neon - 21,5645
B - Boron - 8,298
Li - Lithium - 5,3917
F - Fluorine - 17,4228
N - Nitrogen - 14,5341
Arranged from highest ionization energy to lowest ionization energy.
Ne ; F ; N ; O ; C ; Be ; B ; Li
The formula for Kw is:
Kw= [H]*[OH]
where [H] and [OH] are
concentrations
We are given the pH so we can calculate the [H]
concentration from the formula:
pH=-log[H]
7.43 = -log[H]
[H] = 3.715x10^-8 M
In neutral solution, [H] = [OH], therefore:
<span>[OH]= 3.715x10^-8 M
Calculating Kw:
Kw = (3.715x10^-8)*( 3.715x10^-8)</span>
<span>Kw = 1.38 x 10^-15 </span>
