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Goryan [66]
2 years ago
7

What is the direction of the normal contact force of the road on the wheels?

Physics
1 answer:
Gekata [30.6K]2 years ago
3 0

Answer:

The direction of the contact forces acting on a body is not necessarily perpendicular to the contact surface. The resolution of contact forces in two components i.e. perpendicular to contact surface and along surface. Perpendicular component is normal force and parallel component is friction.

Explanation:

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You are designing an elevator for a hospital. The force exerted on a passenger by the floor of the elevator is not to exceed 1.7
HACTEHA [7]

Answer:

5.62 m/s

Explanation:

Newton's law of motion can be used to determine the maximum speed of the elevator. In the question, we are given:

Force exerted by the elevator (R) = 1.7 times the weight of the passenger (m*g)

Thus: R = 1.7*m*g

Distance (s) = 2.3 m

Newton's second law of motion: R - m*g = m*a

1.7*m*g - m*g = m*a

a = 0.7*m*g/m = 0.7*g = 0.7*9.8 = 6.86 m/s²

To determine the maximum speed:

v^{2} _{f} = v^{2} _{i} + 2as= 0 + 2(6.86)(2.3) = 31.556

v_{f} = \sqrt{31.556} = 5.62 m/s

Therefore, the elevator maximum speed is equivalent to 5.62 m/s.

8 0
2 years ago
Calculate the minimum average power output necessary for a person to run up a 12.0 m long hillside, which is inclined at 25.0° a
Viktor [21]

Answer:

Power, P = 924.15 watts

Explanation:

Given that,

Length of the ramp, l = 12 m

Mass of the person, m = 55.8 kg

Angle between the inclined plane and the horizontal, \theta=25^{\circ}

Time, t = 3 s

Let h is the height of the hill from the horizontal,

h=l\ sin\theta

h=12\times \ sin(25)

h = 5.07 m

Let P is the power output necessary for a person to run up long hill side as :

P=\dfrac{E}{t}

P=\dfrac{mgh}{t}

P=\dfrac{55.8\times 9.8\times 5.07}{3}

P = 924.15 watts

So, the minimum average power output necessary for a person to run up is 924.15 watts. Hence, this is the required solution.

3 0
3 years ago
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
2 years ago
What do we call the material such as air that light travels through
Tcecarenko [31]

Answer:

Transparent or Translucent

Explanation:

7 0
2 years ago
What are the letters that stand for the elements
dalvyx [7]

They are the element symbols. Too many to list here, look up a periodic table.

8 0
3 years ago
Read 2 more answers
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