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allochka39001 [22]
3 years ago
11

Explain why a doctor might not give you any medication if you have a viral disease?

Physics
2 answers:
fomenos3 years ago
5 0

Answer:

You never know if the medication could make you worse

Explanation:

ch4aika [34]3 years ago
3 0

Answer:

I hope it helps you and thank you for helping me

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The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in
lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m

or

\tau=0.5\ N-m

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

6 0
3 years ago
When it reaches an altitude of 3600 m, where the temperature is 5.0∘C and the pressure only 0.68 atm, how will its volume compar
dalvyx [7]

Answer:

The question was incomplete. Here is the complete question.

Explanation:

A helium-filled balloon escapes a child’s hand at sea level and 20.0C. When it reaches an altitude of 3600 m, where the temperature is 5.0∘C and the pressure only 0.68 atm, how will its volume compare to that at sea level?

The ideal gas equation:

PV = nRT

P = absolute pressure

V = Volume of a gas

n = no of moles of a gas

R = ideal gas constant

T = Absolute temperature of a gas

For initial and final states:

P_{i}V_{i} = nRT_{i}   \\P_{f}V_{f} = nRT_{f}   \\\frac{V_{f} }{V_{i} } = \frac{P_{i}T_{f} }{P_{f}T_{i} }

= 1.4

7 0
3 years ago
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). part a part complete find the amplitude
Pani-rosa [81]
The amplitude of a wave corresponds to its maximum oscillation of the wave itself. 
In our problem, the equation of the wave is
y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,
y(x,t)=0.750 cm
and therefore this value corresponds to the amplitude of the wave.
4 0
3 years ago
Read 2 more answers
The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I
erma4kov [3.2K]

Answer:

Part a)

I_{end} = \frac{mL^2}{3}

Part b)

I_{edge} = \frac{2ma^2}{3}

Explanation:

As we know that by parallel axis theorem we will have

I_p = I_{cm} + Md^2

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

I = \frac{mL^2}{12}

now if we need to find the inertia from its end then we will have

I_{end} = I_{cm} + Md^2

I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2

I_{end} = \frac{mL^2}{3}

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

I = \frac{ma^2}{6}

now if we need to find the inertia about an axis passing through its edge

I_{edge} = I_{cm} + Md^2

I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2

I_{edge} = \frac{2ma^2}{3}

7 0
4 years ago
How do you think the amount of a material affects its tendency to sink or float?
Viktor [21]

Answer:

Things float when they are positively buoyant, or less dense than the fluid in which they are sitting. This does not mean that an object has to be lighter than the fluid, as in the case of a boat; objects just need to have a greater ratio of empty space to mass than the fluid.

Explanation:

pls mark as brainliest

6 0
3 years ago
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