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docker41 [41]
3 years ago
14

Which formula can be used to find the magnitude of the resultant vector? R2 = Rx2 + Ry2 R = Rx + Ry R = Rx(cosθ) R = Rx(sinθ)

Physics
2 answers:
Semenov [28]3 years ago
8 0

Answer: R^2 = R_x^2 + R_y^2

Explanation:

when we have two perpendicular vectors Rx and Ry, the magnitude of the resultant vector can be found by using Pythagorean's theorem. In fact, the two vectors Rx and Ry correspond to the two sides of a right triangle, of which the hypothenuse corresponds to the resultant vector R. Therefore, by applying the theorem, we get

R=\sqrt{R_x^2+R_y^2}

which is equivalent to

R^2 = R_x^2+R_y^2

12345 [234]3 years ago
5 0
R^2 = rx^2 + ry^2 !!!!!!!!!!
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Answer:

90 kJ

Explanation:

Work = force × distance

W = (900 N) (100 m)

W = 90,000 J

W = 90 kJ

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3 years ago
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A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise
kiruha [24]

Answer:

h_m=25.8\ m

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=\frac{v_o^2}{2g}

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}

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3 years ago
Which of the following statements about blood alcohol concentration (BAC) are true?
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D) Neither A or B are correct
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2 years ago
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A helicopter is hovering above the ground. Jim reaches out of the copter (with a safety harness on) at 180 m above the ground. A
vesna_86 [32]

Answer:

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

Explanation:

Hi there!

The equation of height and velocity of the package are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the package at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).

v = velocity of the package at a time t.

First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:

v = v0 + g · t

0 = 50.5 m/s - 9.8 m/s² · t

Solving for t:

-50.5 m/s / -9.81 m/s² = t

t = 5.15 s

Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:

h = h0 + v0 · t + 1/2 · g · t²

h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²

h = 140 m

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

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