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antiseptic1488 [7]
2 years ago
8

An object has a mass of 46.5 g and a volume of 55 mL. What is its density?

Chemistry
1 answer:
AveGali [126]2 years ago
4 0

Answer:

0.84545454545 g/ml

Explanation:

to find density do mass/volume

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A lead atom has a mass of 3.14 x 10 to the negative 22nd g.How
frozen [14]

Explanation:

The given data is as follows.

       Mass of a lead atom = 3.14 \times 10^{-22}

       Volume = 2.00 cm^{3}

        Density = 11.3 g/cm^{3}

As it is mentioned that 1 cubic centimeter contains 11.3 grams of lead.

So, in 2 cubic centimeter there will be 2 \times 11.3 g = 22.6 g of lead atoms.

One lead atom has a mass of 3.14 \times 10^{-22}. Therefore, number of atoms present in 22.6 g of lead will be as follows.

                \frac{22.6 g}{3.14 \times 10^{-22}}

                  = 7.197 \times 10^{22} atoms

Thus, we can conclude that there are 7.197 \times 10^{22} atoms of lead are present.

4 0
4 years ago
The question is below
nevsk [136]
The reducing agent is donating electrons and therefore becoming oxidised itself. In this scenario elemental zinc (Zn) is in a reduced state and is oxidised to become Zn2+, in doing so it donates electrons to Fe2+, thereby reducing it to elemental iron (Fe).

The elemental Zinc in solid state is therefore the reducing agent as it reduces Fe2+ to Fe(s).
7 0
3 years ago
10. Aqua means "water" or "a light blue color." Marine refers to the sea. Use this information
Zielflug [23.3K]

Answer:

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=> The colour of this stone is usually a pale greenish blue, owing to the presence of iron impurities. Stones that are treated with heat look more blue than green. On the Mohs scale of hardness, aquamarine ranges between 7.5 and 8 making it a relatively hard gemstone.

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3 0
3 years ago
Read 2 more answers
What is the density of an object if its mass is 10 g and a volume of 2 mL?
Lilit [14]

Hi there! Let's solve this problem shall we!

⠀Volume = 10g

      Mass = 2 mL

In this specific problem, they are asking us to find the <u><em>density </em></u>of the object. So,<u><em> using the information given to us</em></u> (volume and mass), let's solve the problem!

Now, if you remember, D = M ÷ V

So, let's fill in the blanks!

D = Our unknown value

M = 2mL

V = 10g

Here is the filled out formula:

D = M ÷ V

D = 2mL ÷ 10g

D = 5 g/mL

*Make sure you put the units for your final solution!*

4 0
2 years ago
A 9.79 mol sample of freon gas was placed in a balloon. Adding 3.50 mol of freon gas to the balloon increased its volume to 21.8
aivan3 [116]

Answer:

16.06 L was the initial volume of the balloon.

Explanation:

Initial moles of freon in ballon = n_1=9.79 mol

Initial volume of freon gas in ballon = V_1=?

Moles of freon gas added in the balloon = n = 3.50 mole

Final moles of freon in ballon = n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol

Final volume of freon gas in ballon = V_2=21.8 L

Using Avogadro's law:

\frac{V_1}{n_1}=\frac{V_2}{n_2} ( at constant pressure and temperature)

V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L

16.06 L was the initial volume of the balloon.

4 0
3 years ago
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