1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STatiana [176]
3 years ago
12

A 9.79 mol sample of freon gas was placed in a balloon. Adding 3.50 mol of freon gas to the balloon increased its volume to 21.8

L. What was the initial volume of the balloon?
Chemistry
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

16.06 L was the initial volume of the balloon.

Explanation:

Initial moles of freon in ballon = n_1=9.79 mol

Initial volume of freon gas in ballon = V_1=?

Moles of freon gas added in the balloon = n = 3.50 mole

Final moles of freon in ballon = n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol

Final volume of freon gas in ballon = V_2=21.8 L

Using Avogadro's law:

\frac{V_1}{n_1}=\frac{V_2}{n_2} ( at constant pressure and temperature)

V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L

16.06 L was the initial volume of the balloon.

You might be interested in
What are two factors that affect an objects kinetic energy
Bad White [126]
Potential energy and height; best guess;)
8 0
3 years ago
Read 2 more answers
Please Answer ASAP
adelina 88 [10]

The answer to this question would be S2o6 which is C.


3 0
3 years ago
Read 2 more answers
Multiple choice
mihalych1998 [28]

Answer:

S + 4 Cl2

Explanation:

Sulphur - S

1 mol of Sulphur = S

Chlorine = Cl2

4 moles of Chlorine = 4Cl2

4S + 2Cl2

Incorrect option

S + 4 Cl2

Correct option

S + 2Cl2

Incorrect option

S + Cl2

Incorrect option

7 0
3 years ago
Question 4 (1 point)
wlad13 [49]
The answer would be A
4 0
3 years ago
Describe in detail how to prepare 500.0 mL of a 2.5 M calcium chloride solution. Calcium chloride is purchased as a solid. TO pi
antoniya [11.8K]

Answer:

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the solute gets completely soluble add more water up till the mark of 500 ml.

Explanation:

Concentration of calcium chloride = 2.5 M

Volume of the solution = 500.0 ml = 0.5000 L

Moles of calcium chloride = n

c=\frac{n}{V(L)}

n = moles of solute

c = concentration of solution

V = volume of the solution in L

2.5 M=\frac{n}{0.5000 L}

n=2.5 M\times 0.5000 L = 1.2500 mol

n=\frac{\text{Mass of calcium chloride}}{\text{Molar mass of calcium chloride}}

1.2500 mol=\frac{\text{Mass of calcium chloride}}{111 g/mol}

Mass of calcium chloride = 111 g/mol × 1.2500 mol = 138.75 g

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the the solute gets completely soluble add more water up till the mark of 500 ml.

4 0
3 years ago
Other questions:
  • A compound is a substance composed of two or more elements that are
    15·1 answer
  • How many mol of nitrogen is in 0.30 mol of caffeine
    10·2 answers
  • According to Le Châtelier’s Principle, the amount of solid reactant or product present does not have an impact on the equilibriu
    9·1 answer
  • let 4 moles of methanol (liquid) combust in 3 moles of gaseous oxygen to form gaseous carbon dioxide and water vapor. Suppose th
    12·1 answer
  • A chemical equation is shown below. KNO3 → KNO2 + O2 What are the coefficients that should be added to balance this equation? Us
    9·2 answers
  • The study of metals and the process for refining and making things from them is called _____.
    5·2 answers
  • What layer of the skin provides insulation and keeps us warm?
    8·2 answers
  • What are the two basic ways in which ions form from atoms?
    11·1 answer
  • An atom of the element iron has an atomic number of 26 and an atomic weight of 56. if it is neutral, how many protons, neutrons,
    10·1 answer
  • What does every food energy chain start with?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!