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frozen [14]
2 years ago
9

What is electrons configuration for arsenic ?

Chemistry
1 answer:
Anna35 [415]2 years ago
7 0

Answer:

[Ar] 3d¹⁰ 4s² 4p³

Explanation:

so...... ur welcome

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Why do we need an isolated system for the law of conservation of mass to be true?
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The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

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Given the standard enthalpies of formation for the following substances, determine
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Ammonia gas can be prepared by the reaction CaO ( s ) + 2 NH 4 Cl ( s ) ⟶ 2 NH 3 ( g ) + H 2 O ( g ) + CaCl 2 ( s ) In an experi
bogdanovich [222]

The given question is incomplete. The complete question is ;

Ammonia gas can be prepared by the following reaction:

CaO(s)+2NH_4Cl(s)\rightarrow 2NH_3(g)+H_2O(g)+CaCl_2(s)

In an experiment, 27.6 g of ammonia gas, NH_3, is produced when it was predicted that 50.2 g of NH_3 would form.

What is the theoretical yield of NH_3? What is the actual yeild of NH_3? What is the percent yeild of NH_3?

Answer: a) 50.2 g

b) 27.6 g

c) 5.0 %

Explanation:

a) Theoretical yield is defined as the amount of the product that is possible in the reaction.

Theoretical yield of NH_3 = 50.2 g

b) Experimental or actual yield is defined as the amount of the product that is actually formed in the reaction.

Experimental yield of NH_3 = 27.6 g

c) Percentage yield is defined as the ratio of experimental yileld to the theoretical yield in terms of percentage.

{\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%

{\text {percentage yield}}=\frac{27.6g}{50.2g}\times 100\%=55.0\%

Hence percentage yield for the reaction is 55.0 %.

3 0
3 years ago
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