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2 years ago

Differences between sublimation and condensation

Physics

1 answer:

zaharov [31]2 years ago

5 0

The difference between sublimation and condensation is that

Sublimation is used to in a separation technique to separate sublime substance from a mixture while condensation is the

is the process where water vapor becomes liquid

<h3>What is separation technique?</h3>

This technique is used in chemistry to separate two or more constituents from a mixture

In conclusion, sublimation differs from condensation because sublimation is used to in a separation technique to separate sublime substance from a mixture while condensation is the

is the process where water vapor becomes liquid

Learn more about separation technique:

brainly.com/question/10862519

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a catapult is used to project a stone of mass 50g. if the rubber of the catapult has an elastic constant of 200N/m and was stret

Anna35 [415]

Answer:

3.16 m/s

Explanation:

Elastic energy in the rubber = kinetic energy of the stone

EE = KE

½ kx² = ½ mv²

v = √(kx²/m)

Given k = 200 N/m, x = 0.05 m, and m = 0.050 kg:

v = √(200 N/m (0.05 m)² / 0.050 kg)

v = √10 m/s

v ≈ 3.16 m/s

Round as needed.

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3 years ago

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A person starts to run around a square track with sides of 50 m starting in the bottom right corner and running counter-clockwis

nikdorinn [45]

Answer:3.71 m/s

Explanation:

Given

square track with sides 50 m

average speed is 5 m/s

Total running time=53.8 s

Total distance traveled in this time $=53.8\times 5=269 m$

i.e. Person has completed square track one time and another 69 m in second round

So displacement is 269-200=69 m

average velocity $=\frac{Displacement}{time}$

$=\frac{69}{53.8}=1.28 m/s$

Difference between average velocity and average speed is

5-1.28=3.71 m/s

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3 years ago

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What is the distance to a star whose parallex is 0.1 sec?

Arte-miy333 [17]

Answer:

$30.86\times 10^{13} km$

Explanation:

Given the parallex of the star is 0.1 sec.

The distance is inversely related with the parallex of the star. Mathematically,

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Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.

Now,

$d=\frac{1}{0.1}\\d=10 parsec$

And also know that,

$1 parsec=3.086\times 10^{13} km$

Therefore the distance of the star is $30.86\times 10^{13} km$ away.

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3 years ago

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madam [21]

Answer:

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Explanation:

It seems like the most spontaneous sport there

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3 years ago

A train is uniformly accelerated and passes

cupoosta [38]

Answer:

Explanation:

18 km/hr(1000 m/km) / (3600 s/hr) = 5 m/s

36 km/hr = 10 m/s

v² = u² + 2as

a = (v² - u²)/2s

a = (10² - 5²)/2(1000) = 0.0375 m/s²

v² = 10² + 2(0.0375)(1000)

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t = (13.22875 - 10) / 0.0375 = 86.1 s

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3 years ago