Answer:
Explanation:
Let m be the mass of cylinder and r be the radius. It is moving with velocity v and angular velocity is ω. Let I be the moment of inertia of the cylinder.
I = 0.5 mr²
Total kinetic energy, T = 0.5 mv² + 0.5 Iω²
T = 0.5 (mv² + 0.5 mr²ω²)
v = rω
So, T = 0.5 (mv² + 0.5 mv²) = 0.75 mv²
Rotational kinetic energy is
R = 0.5 Iω² = 0.5 x 0.5 mr²ω²
R = 0.25 mv²
So, R / T = 0.25 / 0.75 = 1/3
Answer: 586.60N/m
Explanation:
In this scenario, the elastic potential energy of the spring is converted into potential energy.
0.5*K*x^2 = mgh
Thus K = 2mgh/x^2
=(2*2.90*10^-2*9.8*7.23)/(8.37*10^-2)^2
=586.599
Therefore K = 586.60N/m
TRUE. When you approach a yield sign, while trying to enter or merge onto another road, traffic already on that road has the right of way.
Answer:
The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447
Explanation:
We are given that A city of Punjab has 15 percent chance of wet weather on any given day.
So, Probability of wet weather = 0.15
Probability of not being a wet weather = 1-0.15 =0.85
We are supposed to find probability that it will take a week for it three wet weather on 3 separate days
Total number of days in a week = 7
We will use binomial over here
n = 7
p =probability of failure = 0.15
q = probability of success=0.85
r=3
Formula :
Standard deviation =
Standard deviation =
Standard deviation =0.9447
Hence The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447
Answer:
V= 6.974 m/s
Explanation:
Component( box) weight acting parallel and down roof 88(sin39.0°)=55.4 N
Force of kinetic friction acting parallel and up roof = 18.0 N
Fnet force acting on tool box acting parallel and down roof
Fnet= 55.4 - 18.0
Fnet=37.4 N
acceleration of tool box down roof
a = 37.4(9.81)/88.0
a= 4.169 m/s²
d = 4.90 m
t = √2d/a
t= √2(4.90)/4.169
t= 1.662 s
V = at
V= 4.169(1.662)
V= 6.974 m/s
