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Damm [24]
2 years ago
13

A magnet gets demagnetized when it is heated.​

Physics
1 answer:
muminat2 years ago
6 0

Answer:

The delicate balance between temperature and magnetic domains is destabilized when a magnet is subjected to high temperatures. If a magnet is exposed to this temperature for an extended length of time or heated over its Curie temperature, it will lose its magnetism and become irreversibly demagnetized.

Explanation:

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the length of time it takes a planet to revolve around the sun is equivalent to witch of the following?
Marina86 [1]
It really depends on how far or close the planet is from the sun

6 0
3 years ago
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The wave length of violet light rounded to the nearest nanometer is a __ nm
nataly862011 [7]
Wavelength= speed / frequency 

so.....3× 10^8 / 7.26×10^14
= .413× 10^(-6)

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6 0
3 years ago
Which of the following represents the wavelength of a wave?
dlinn [17]

Answer: D. the distance between the highest points of consecutive waves

Explanation:

The wavelength of a wave is defined as the <em>distance traveled by a periodic perturbation that propagates through a medium in a given time interval</em>. It is usually represented by \lambda and can be calculated if the frequency of the wave is known, since there is an inverse relationship between both.

In the specific case of a periodic sine wave (which is the way in which a wave is usually represented graphically) the wavelength can be determined as the distance between two consecutive maxima of the disturbance.

Therefore, the correct option is D.

8 0
3 years ago
Read 2 more answers
At the north magnetic pole the earth’s magnetic field is vertical and has a strength of 0.62 gauss. The earth’s field at the sur
Anika [276]

Answer:

A) Dipole moment; m = 8.02 x 10^(22) J/T

B) I = 3.51 x 10^(9) A

Explanation:

The components of a magnetic field of a dipole are;

B_r = (μ_o•m/2πr³).cosθ

B_θ = (μ_o•m/4πr³).sin θ

B_Φ = 0

Let's make m the subject in the B_r equation ;

m = (2πr³•B_r)/(μ_o•cosθ)

Where;

B_r is magnetic field = 0.62 Gauss = 6.2 x 10^(-5) T

μ_o is the magnetic constant and has a value of 4π × 10^(−7) H/m

m is magnetic moment.

r is equal to radius of earth =6.371 x 10^(6)m

Thus, if we set θ = 0,we can solve for m as below;

m = (2π(6.371 x 10^(6))³•6.2 x 10^(-5) )/(4π × 10^(−7)•cos0)

Thus, m = 8.02 x 10^(22) J/T

B) Now, to find the current, let's use the expression for the magnetic field on the z-axis of the current ring.

B_z = (μ_o•Ib²/(2(z² + b²/2)^(3/2)))

So, let's set z = R and b = R/2

Thus, we now have;

B_z = (μ_o•I)/(5^(3/2)•R)

Making I the subject, we have;

I = [(5^(3/2)•R)•B_z]/μ_o

Plugging in the relevant values, we have;

I = [(5^(3/2) x 6.371 x 10^(6)) x 6.2 x 10^(-5)]/(4π × 10^(−7))

I = 3.51 x 10^(9) A

4 0
4 years ago
Appropriate word inside the parentheses.
Taya2010 [7]

Answer:

<em>At constant mass, the  acceleration of an object varies (</em><em>directly</em><em>) with the net external force  applied. That is to say, that an object's acceleration increases as the force applied is (</em><em>increased</em><em>),  but its acceleration decreases if the force applied is (</em><em>decreased</em><em>).</em>

Explanation:

<u>Mechanical Force </u>

According to the second Newton's law, the acceleration of an object varies directly proportional to the external net force applied and inversely proportional to the mass of the object.

If the mass is constant, then the acceleration will vary in the same way as the force does.

Completing the sentences:

At constant mass, the  acceleration of an object varies (directly) with the net external force  applied. That is to say, that an object's acceleration increases as the force applied is (increased),  but its acceleration decreases if the force applied is (decreased).

6 0
3 years ago
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