An unstrained horizontal spring has a length of 0.31 m and a spring constant of 220 N/m. Two small charged objects are attached
1 answer:
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Answer:
The found acceleration in terms of h and t is:
Explanation:
(The complete question is given in the attached picture. We need to find the acceleration in terms of h and t in this question)
We are given 3 stages of movement of elevator. We'll first model them each of the stage one by one to find the height covered in each stage. After that we'll find the total height covered by adding heights covered in each stage, and equate it to Total height h. From that we can find the formula for acceleration.
<h3></h3><h3>Stage 1</h3>Constant acceleration, starts from rest.
Distance =
Velocity =
Constant velocity where
Velocity =
Distance =
<h3>Constant deceleration where
Velocity =
Distance =
Total height = y₁ + y₂ + y₃
Total height =
Find acceleration by rearranging the found equation of total height.
Total Height = h
h = 5a(t₁)²
To increase the centripetal acceleration to , you can double the speed or decrease the radius by 1/4
Explanation:
An object is said to be in uniform circular motion when it is moving at a constant speed in a circular path.
The acceleration of an object in uniform circular motion is called centripetal acceleration, and it is given by
where
v is the speed of the object
r is the radius of the circular path
In the problem, the original centripetal acceleration is
We want to increase it by a factor of 4, i.e. to
We notice that the centripetal acceleration is proportional to the square of the speed and inversely proportional to the radius, so we can do as follows:
- We can double the speed:
v' = 2v
This way, the new acceleration is
so, 4 times the original acceleration
- We can decrease the radius to 1/4 of its original value:
So the new acceleration is
so, the acceleration has increased by a factor 4 again.
Learn more about centripetal acceleration:
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