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3 years ago

A parallel plate capacitor can store

2 answers:

4 0

Hey, there! Great question:) Answer: Electric charge AND electric energy. I hope this helps;) If you have any questions based on my work, feel free to ask=)

Norma-Jean [14]3 years ago

3 0

A parallel plate capacitor can store electric charge and
electrical energy, and if the plates are far enough apart,
you can store your lunch in there too.

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Salmon often jump waterfalls to reach their breeding grounds starting downstream, 2.9 meters away from a waterfall .436 meters i

nikklg [1K]

The minimum speed must a Salmon jumping with to leave the water

to continue upstream is 5.79 m/s

Explanation:

At first let us find the two component of the jumping velocity of the fish

1. Horizontal component $u_{x}$ = u cosФ

2. Vertical component $u_{y}$ = u sinФ

where u is the initial velocity and Ф is the angle between the horizontal

and the initial velocity u

→ Ф = 44.7°

→ $u_{x}$ = u cos(44.7)

→ $u_{y}$ = u sin(44.7)

The horizontal distance x is 2.9 meters away from a waterfall

The vertical distance y is 0.436 meters

3. The horizontal distance x = $u_{x}$ t

4. The vertical distance y = $u_{y}$ t + $\frac{1}{2}$ gt²

where g is the acceleration of gravity

→ x = u cos(44.7) t

→ x = 2.9 meters

→ 2.9 = u cos(44.7) t

Divided both sides by u cos(44.7)

→ t = $\frac{2.9}{ucos(44.7)}$ ⇒ (1)

→ y = u sin(44.7) t + $\frac{1}{2}$ gt²

→ y = 0.436 meters , g = -9.81 m/s²

→ 0.436 = u sin(44.7) t - 4.905 t² ⇒ (t)

Substitute (1) in (2) to make the equation of u only

→ 0.436 = u sin(44.7)( $\frac{2.9}{ucos(44.7)}$ ) - 4.905 ( $\frac{2.9}{ucos(44.7)}$ )²

→ 0.436 = 2.9 ( $\frac{sin(44.7)}{cos(44.7)}$ - $\frac{41.25105}{u^{2}[cos(44.7)]^{2}}$

→ 0.436 = 2.8698 - $\frac{81.4671}{u^{2} }$

Subtract 2.8698 from both sides

→ -2.4338 = - $\frac{81.4671}{u^{2} }$

Multiply both sides by -1

→ 2.4338 = $\frac{81.4671}{u^{2} }$

By using cross multiplication

∴ 2.4338 u² = 81.4671

Divide both sides by 2.4338

→ u² = 33.4732

Take √ for both sides

→ u = 5.79 m/s

The minimum speed must a Salmon jumping with to leave the water

to continue upstream is 5.79 m/s

Learn more:

You can learn more about the equation of trajectory of the projectile in brainly.com/question/2814900

brainly.com/question/5531630

#LearnwithBrainly

4 0

3 years ago

A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 4500 N/C and is directed in

Anton [14]

Answer with Explanation:

We are given that

$E=4500 N/C$

$q=-5.5\times 10^{-9} C$

a.x=-0.2 m

$E'=\frac{Kq}{r^2}=\frac{9\times 10^9\times 5.5\times 10^{-9}}{(0.2)^2}=1237.5 N$

Where $k=9\times 10^9$

Net electric field=E+E'=4500+1237.5=5737.5 N/C

b.x=0.20 m

Net electric field=E-E'=4500-1237.5=3262.5 N/C

c.y=0.20 m

E=1237.5 N/C

Net electric field= $\sqrt{E^2+E'^2}=\sqrt{(4500)^2+(1237.5)^2}=4667.05 N/C$

7 0

3 years ago

Please help with 5 & 6!

Paul [167]

Answer: sorry but I can’t help

Explanation:because I can’t see it

6 0

3 years ago

Which statement describes nuclear fission

Harlamova29_29 [7]

The Splitting of a nucleus

3 0

3 years ago

Read 2 more answers

1. Draw magnetic field (B field) line diagrams for the following. Make sure the diagrams are large enough so the direction and s

larisa [96]

I attached the requested diagram.

In the case of the magnetic field in a bar by convention, the direction of the field is taken out of the north pole and towards the south pole of the magnet. These types of images are commonly made of some ferrous material.

In the case of the horseshoe magnet, the highly concentrated magnetic field is distinguished between its legs. In the figure it is shown in a contribution from North to South, again by agreement, however outside the two poles, the magnetic field falls rapidly. A horseshoe magnet is basically a bent bar magnet.

4 0

3 years ago